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2 years ago

Using the quadratic formula, which of the following are the zeros of the

Mathematics

1 answer:

Naddika [18.5K]2 years ago

3 0

Answer:

The answer is the option A.

x=(5±)/4

Step-by-step explanation:

The quadratic formula has the following form for a quadratic equation ax²+bx+c:

x=(-b±))/(2a)

We apply the quadratic formula and we obtain:

x=(-(-5)±))/(2(2))

x=(-(-5)±))/(4)

brainliest pls

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Find the value of z in the isosceles triangle shown below.<br> V20<br> V20<br> 8

Shkiper50 [21]

Answer:

Step-by-step explanation:

use Pythagorean theorem:

a² + b² = c²

where a = x

b = 8/2 = 4

c = √20

plugin values into the formula:

x² + 4² = (√20)²

x² + 16 = 20

x² = 20 - 16

x = √4

x = 2

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3 years ago

Enter the unknown value that makes this statement true: 20% of ? is 40.

elixir [45]

Answer: 20% of 200= 40

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3 years ago

Select the correct answer. Which point is a solution of x + 2y ≤ 4? A. (2, 4) B. (1, 1) C. (3, 5) D. (-1, 5)

stira [4]

Answer:

Step-by-step explanation:

Of you put the values of c and y from B in the equation, then the result is,

$1 + 2 \times 1 \leqslant 4 \\ 1 + 2 \leqslant 4 \\ 3 \leqslant 4$

here, 3 is less than 4, which is true.

But the result will come out as greater than 4 if you put other points in the equation, which is not true for the given condition.

6 0

3 years ago

Ingredients for 7 cakes

lisabon 2012 [21]

Answer:

He made 5 cakes

Step-by-step explanation:

49 divided by 7 = 7

56 divided by 7 = 8

70 divided by 7 = 10

63 divided by 7 = 9

So for one cake you would need 7 g sugar, 8 g butter, 10 g flour, and 9 ml milk. So, 50 divided by 10 = 5 cakes

3 0

3 years ago

Read 2 more answers

What is the average (arithmetic mean) of eleven consecutive integers? (1) the average of the first nine integers is 7. (2) the a

laiz [17]

Since eleven is odd, there must be a centra element, which in this case is the sixth. So, we can write 11 consecutive integers as

$x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5$

Since the arithmetic mean is the sum of the values, divided by how many they are, we have

$M = \dfrac{x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5}{11} = \dfrac{11x}{11} = x$

So, the mean of 11 consecutive integers is the 6th integer.

4 0

3 years ago