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1 year ago

A square has a side length of n + 6. A rectangle has length n + 15 and width of

Mathematics

1 answer:

kogti [31]1 year ago

4 0

Answer:

I'm pretty sure you have to add everything

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14)If you multiply John's age by 4 and then

natulia [17]

Answer:

there was alot of math here but i got 10

Step-by-step explanation:

so first u add 10 and 2 u get 12 then u multiply 4 then u get 48 and divide that by 4 and then subtract 2 and get 10. hope this helped

6 0

2 years ago

An NBC News/Wall Street Journal poll conducted in 2010 predicted that 61% of Americans did not support the Tea Party movement. I

fomenos

Answer:

The right answer is:

The poll provides strong evidence that more than 61% of Americans oppose the Tea Party movement this year. Why? The P-value (0.026) is less than the significance level of 5%.

Step-by-step explanation:

At a level of significance of 5%, a P-value of 0.026 (2.6%) means that the difference is significant and the null hypothesis is rejected.

The difference between the proportions is significant, what means that more than 61% of Americans oppose the Tea Party movement this year.

Note: The difference in the sample proportions (3%) is not enough to claim that the difference is significant.

The right answer is:

The poll provides strong evidence that more than 61% of Americans oppose the Tea Party movement this year. Why? The P-value (0.026) is less than the significance level of 5%.

5 0

3 years ago

18,000 divided by 25%

DanielleElmas [232]

Correct answer - 72000.

7 0

2 years ago

Read 2 more answers

A number cube is rolled two times in a row. What is the probability of rolling a three both times

Kay [80]

Answer:

There would be a 1/36 chance.

6 0

2 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

kompoz [17]

$f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}$

is a proper joint density function if, over its support, $f$ is non-negative and the integral of $f$ is 1. The first condition is easily met as long as $C\ge0$ . To meet the second condition, we require

$\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}$

b. Find the marginal joint density of $X$ and $Y$ by integrating the joint density with respect to $z$ :

$f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz$

$\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}$

Then

$\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy$

$\approx\boxed{0.12886}$

c. This probability can be found by simply integrating the joint density:

$\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz$

$\approx\boxed{0.012262}$

7 0

2 years ago