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2 years ago

Help please! Identify an equation in point slope form for the line perpendicular to Y =-1/2x+11that passes through (4,-8)

Mathematics

1 answer:

juin [17]2 years ago

6 0

Answer:

y=2x+8

Step-by-step explanation:

You set the slope to the opposite of -1/2 which is 2/1 or 2.

Then you do b=2(4) (because 4 is the x in the coordinate points)

and solve for b you get 8 so

Y=2x+8

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Find all the zeros of 2x4+x3-14x2-19x-6 two of its zeros are -2 and -1

GalinKa [24]

Answer:

$-2,\ -1,\ -\dfrac{1}{2},\ 3.$

Step-by-step explanation:

Consider polynomial $2x^4+x^3-14x^2-19x-6.$

If x=-2 is its zero, then you can divide the polynomial $2x^4+x^3-14x^2-19x-6$ by $x+2$ and get

$2x^4+x^3-14x^2-19x-6=(x+2)(2x^3-3x^2-8x-3).$

If x=-1, then the polynomial $2x^4+x^3-14x^2-19x-6$ can be rewritten as

$2x^4+x^3-14x^2-19x-6=(x+2)(x+1)(2x^2-5x-3).$

The quadratic polynomial has roots

$x_{1,2}=\dfrac{-(-5)\pm\sqrt{(-5)^2-4\cdot2\cdot(-3)}}{2\cdot 2}=\dfrac{5\pm \sqrt{25+24}}{4}=\dfrac{5\pm \sqrt{49}}{4}=3,-\dfrac{1}{2}.$

Then the polynomial $2x^4+x^3-14x^2-19x-6$ has zeros $-2,\ -1,\ -\dfrac{1}{2},\ 3.$

7 0

3 years ago

-7y = -77 solve for y

babunello [35]

Y=11
is the answer to your question! <3

5 0

3 years ago

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506 students went on a field trip. Nine buses

vampirchik [111]

Answer:

53 students on each bus

Step-by-step explanation:

506-29=477 (take out the students that went by car)

477/9 = 53 (distribute 477 students evenly in 9 buses)

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3 years ago

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Which of the following lines has a negative slope?

Furkat [3]

Answer:

The second option, or the one attached.

Step-by-step explanation:

This line has a negative slope because the line is going "down the stairs" from the top-left to the bottom-right.

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3 years ago

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(X^2+y^2)^2 polynomial identify. Simplify

Alexxx [7]

Answer:

$(x^{2}+ y^{2})^{2} =x^{4}+2x^{2}y^{2}+y^{4}$

Step-by-step explanation:

(X^2+y^2)^2 polynomial identify. Simplify

i.e

$(x^{2}+ y^{2})^{2} = ?$

Solution:

We have the identity,

$(A+B)^{2}=A^{2}+2AB+B^{2}$

In the Question

$A=x^{2}$

$B=y^{2}$

Substituting in the identity we get

$(x^{2}+ y^{2})^{2} =(x^{2})^{2}+2(x^{2})(y^{2})+(y^{2})^{2}$

Also we have

$(x^{a})^{b} =x^{a\times b}$

$(x^{2}+ y^{2})^{2} =x^{4}+2x^{2}y^{2}+y^{4}$ Which is the required

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4 years ago