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Vlad1618 [11]
3 years ago
7

What part of the cover letter explains how the applicant’s qualifications meet the needs of the company?

Computers and Technology
2 answers:
liubo4ka [24]3 years ago
6 0
The answer is D! Hope this Helps.
kakasveta [241]3 years ago
5 0
The correct answer is C. Argument. 

Next time, learn how to put the whole question.
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nydimaria [60]
If an iphone go to the open book icon then go to history and clear from there if on a laptop go to the top right and look at the three ... press it and go to history and press clear history I don’t remember about android
4 0
3 years ago
Read 2 more answers
A sinewave has a period (duration of one cycle) of 645 μs. What is the corresponding frequency of this sinewave, in kHz, express
irga5000 [103]

The corresponding frequency of this sinewave, in kHz, expressed to 3 significant figures is: <em>155 kHz.</em>

<u>Given the following data:</u>

  • Period = 645 μs

Note: μs represents microseconds.

<u>Conversion:</u>

1 μs = 1 × 10^{-6} seconds

645 μs = 645 × 10^{-6} seconds

To find corresponding frequency of this sinewave, in kHz;

Mathematically, the frequency of a waveform is calculated by using the formula;

Frequency = \frac{1}{Period}

Substituting the value into the formula, we have;

Frequency = \frac{1}{645\; * \;10^{-6}}

Frequency = 1550.39 Hz

Next, we would convert the value of frequency in hertz (Hz) to Kilohertz (kHz);

<u>Conversion:</u>

1 hertz = 0.001 kilohertz

1550.3876 hertz = X kilohertz

Cross-multiplying, we have;

X = 0.001 × 1550.39

X = 155039 kHz

To 3 significant figures;

<em>Frequency = 155 kHz</em>

Find more information: brainly.com/question/23460034

5 0
3 years ago
When a hostname is configured through the cisco cli, which three naming conventions are part of the guidelines? (choose three.)?
Advocard [28]
When a hostname is configured through the Cisco cli,  there are some naming <span>conventions are part of the guidelines that should be followed.

From these conventions:
1- the name of the host shouldn't contain any spaces.
2- the name of the host should always begin with a letter
3- the name of the host should be less than 64 characters in length.</span>
3 0
4 years ago
Consider this program segment: int newNum = 0, temp; int num = k; // k is some predefined integer value 0 while (num &gt; 10) {
Doss [256]

Answer:

All of these statements are true.

Explanation:

Since the while loop is reversing the integer number and leaving the highest order digit in the num and stores the reversed number in the newNum variable.

It skips one digit so if the num is in the range of [100,1000] it will result in a number between 10 and 100.

This loop can never go in infinite loop for any initial value of num because the loop will run as many times as the number of digits.

and if the value of the num is <=10 the while loop will never run and the value of newNum will be 0.

6 0
4 years ago
Write a method transpose, that takes as argument a 2D array of integers, myTable, and returns the transpose of myTable. The tran
Gelneren [198K]

Answer:

The program to this question can be given as:

Program:

import java.util.*; //import package

public class Main //defining class

{

public static int[][] transpose(int[][] a1) //defining function transpose

{

int i,j; //define variables

int[][] transpose = new int[a1[0].length][a1.length]; //define variable transpose.

//loop for transpose matrix.

for(i = 0; i < a1.length; i++)  

{

for(j = 0; j < a1[i].length; j++)

{

transpose [j][i] = a1[i][j]; //hold value in transpose variable

}

}

return transpose ; //return transpose matrix.  

}

public static void main(String[] args) //main method.

{

int row,col,i,j; //defining variable.

Scanner obj = new Scanner(System.in); //creating Scanner class Object

System.out.print("Enter number of rows: ");//message

row = obj.nextInt(); //input rows form user.

System.out.print("Enter number of columns: ");//message

col = obj.nextInt(); //input columns form user.

int[][] a1 = new int[row][col]; //defining array.

System.out.println("Enter matrix"); //message

// loop for input array elements from user

for(i=0; i<a1.length;i++)  

{

for(j=0; j<a1[i].length;j++)  

{

a1[i][j]=obj.nextInt(); //input in array variable.

}

}

System.out.println("Matrix you insert :"); //message

// loop for display array.

for(i=0; i<a1.length;i++)  

{

for(j=0; j<a1[i].length;j++)  

{

System.out.print(a1[i][j]+" "); //print matrix

}

System.out.print("\n");

}

int[][] result = transpose(a1); //define result array variable that holds function value.

System.out.println("Transposed matrix is :");

//use loop for print Transpose matrix.

for(i = 0;i < result.length;i++)

{

for (j = 0; j < result[i].length;j++)

{

System.out.print(result[i][j] + " "); //print matrix

}

System.out.print("\n");

}

}

}

Output:

Enter number of rows: 2

Enter number of columns: 3

Enter matrix

2

3

4

9

8

7

Matrix you insert :

2 3 4  

9 8 7  

Transposed matrix is :

2 9  

3 8  

4 7  

Explanation:

The description of the above program can be given as:

  • In the above program firstly import a package, then declare a class that is "Main" inside a class defining a transpose() function this function returns a matrix in transpose form.
  • In the main class, we define a variable and matrix that is "row, col, i, j and a1[][]".  Then we Creating a scanner class object, which is used by row, col and a1[][] variables for user input.  
  • The row and col variables are used to declare matrix size and i, j variable is used in the loop for insert and display matrix.  
  • a1[][] matrix is used for input matrix elements and passes into transpose() function as an argument that returns a value that is held in the result variable. This is used as a loop for the print transpose matrix.

5 0
3 years ago
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