Answer:
1/4=z/20. This deals with adding, subtracting and finding the least common multiple. Overview; Steps; Topics Terms and topics;
Step-by-step explanation:
so we know X= Numbers of Large boxes and Y= Numbers of Small boxes
And we know the large boxes weigh <em>7</em><em>5</em><em><u> </u></em><em><u>pounds</u></em> and the small boxes weigh <em>4</em><em>0</em><em> </em><em><u>pounds</u></em>
So I would have to say the the same except you have to flip the inequality sign like this:
75x + 40y
![\geqslant \\](https://tex.z-dn.net/?f=%20%5Cgeqslant%20%20%5C%5C%20)
200
And if that doesnt somehow work and the question is wording it wrong then
My guess for why its wrong us because its not in slope intercept form Although you still can solve for either varible ( x or y) using standard form also.
So to get from standard form to Slope intercept form (y=mx+b) these are the steps:
Ax+by=C
75x + 40y ≤ 200
Turn it into a linear equation.
75x+ 40y =200
In order to go from one form to another, all you have to do is change the order of the given numbers. First you want to move the Ax to the opposite side of the equation, by either adding or subtracting it. At this point your equation will be set up By = -Ax + C. Then you want to divide the B from the By and the rest of the equation. Therefore you will have y = - Ax/B + C/B. This is the same thing as the slope-intercept form, just a few of the letters are different.
40y=-75x+200 first subtract 75x
y=−1.875×+5 then dived every varible (everything) by 40. and you have your Linear eqaution.
And your second question would be <em><u>A</u></em><em><u>.</u></em><em><u> </u></em><em><u>>The number of boxes must be a whole number.</u></em><em><u> </u></em>
Because you cannot split boxes in half or in any quarter in a real life scenario.
Correct answers are
and
i.e. Options A & D
<u>Step-by-step explanation:</u>
Options for this questions are:
A)D+1/5D
B)D+20
C)D+20D
D)1.2D choose two answers.
We have , Crispy Clover, a popular vegetarian restaurant, introduced a new menu that has 20%, percent more dishes than the previous menu. The previous menu had D dishes.We need to find expressions could represent how many dishes Crispy Clover's new menu has . Let's find out:
Initially , Number of dishes are D . Then 20% more dishes are there in menu
⇒ ![\frac{D(20)}{100}](https://tex.z-dn.net/?f=%5Cfrac%7BD%2820%29%7D%7B100%7D)
So , Total Number of Dishes are
⇒ ![D + \frac{20d}{100}](https://tex.z-dn.net/?f=D%20%2B%20%5Cfrac%7B20d%7D%7B100%7D)
⇒ ![D + \frac{20d}{20(5)}](https://tex.z-dn.net/?f=D%20%2B%20%5Cfrac%7B20d%7D%7B20%285%29%7D)
⇒ ![D + D(\frac{1}{5})](https://tex.z-dn.net/?f=D%20%2B%20D%28%5Cfrac%7B1%7D%7B5%7D%29)
⇒ ![D + D(0.2)](https://tex.z-dn.net/?f=D%20%2B%20D%280.2%29)
⇒ ![1.2D](https://tex.z-dn.net/?f=1.2D)
Therefore, Correct answers are
and
i.e. Options A & D .
Answer:
.
Step-by-step explanation: We are given expression
.
And
expression is converted in
.
Now, we need to transform the expression into a single exponent expression using the properties of exponents.
We know, according to the properties of exponents
![(a^m)^n = a^{m\times n}](https://tex.z-dn.net/?f=%28a%5Em%29%5En%20%3D%20a%5E%7Bm%5Ctimes%20n%7D)
Applying same rule in given expression, we get
![(1.06^{1/2})^{2t} = (1.06)^{\frac{1}{2} \times 2t}](https://tex.z-dn.net/?f=%281.06%5E%7B1%2F2%7D%29%5E%7B2t%7D%20%3D%20%281.06%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%202t%7D)
On simplifying exponents, we would get t in exponent.
=
.