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julia-pushkina [17]
2 years ago
14

5. The cost per person to rent a chartered bus varies inversely to the number of people a who ride the bus. If 40 people pay $9.

50 each to ride the chartered bus, what is the cost per person if only 25 people go?
the answers are
a. $24.50
b. $5.94
c. $15.20
d. $380.00​
Mathematics
1 answer:
777dan777 [17]2 years ago
3 0
Answer d $380.00 or answer a $24.00
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A can of pineapple has a height of 13 cm and a diameter of 10 cm, What is the surface of the label that is on it in cm^2
labwork [276]

Answer:

408.46cm^2

Step-by-step explanation:

Given data

Height= 13cm

Diameter= 10cm

Radius= D/2= 10/2= 5cm

The area of the curved surface will be = 2πr × h = 2πrh

substitute

Area of the curved surface = 2πrh= 2*3.142*5*13

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Step-by-step explanation:

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A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. ​(a) What must be true
valentina_108 [34]

Answer:

(a) The distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b) The value of P(\bar X is 0.7642.

(c) The value of P(\bar X\geq 69.1) is 0.3670.

Step-by-step explanation:

A random sample of size <em>n</em> = 10 is selected from a population.

Let the population be made up of the random variable <em>X</em>.

The mean and standard deviation of <em>X</em> are:

\mu=68\\\sigma=15

(a)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. <em>n</em> = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

\mu_{\bar x}=\mu=68

And the standard deviation of the distribution of the sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74

Thus, the distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b)

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the value of P(\bar X is 0.7642.

(c)

Compute the value of P(\bar X\geq 69.1) as follows:

Apply continuity correction as follows:

P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)

                    =P(\bar X>69.6)

                    =P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})

                    =P(Z>0.34)\\=1-P(Z

Thus, the value of P(\bar X\geq 69.1) is 0.3670.

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vredina [299]

Answer:

B

Step-by-step explanation:

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