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Sonja [21]
3 years ago
6

What is the nth term rule of the quadratic sequence below? 6,12,20,30,42,56,72

Mathematics
2 answers:
natali 33 [55]3 years ago
4 0

The ninth term is 110 beacsue you are adding two every time.

HOPE THIS HELPS!

HAVE A GR8 DAY ;-)

const2013 [10]3 years ago
3 0

Answer:

n(squared)^2 + 3n + 4.

Step-by-step explanation:

<h3>Sequence: 6, 12, 20, 30, 42, 56, 72.</h3>

First, lets find the first difference between the numbers. (In other words, let find the number gap difference between the first, second, third, fourth, fifth, sixth and seventh term).

In this case, it'll be..

first difference = 6.

second difference = 8.

third difference = 10.

fourth difference = 12.

fifth difference = 14.

sixth difference = 16.

Now we have the differences between the numbers, we need to do the second difference, which in this case is 3, meaning you have 3n.

Then, you would find out that n(squared)^2, is gonna be part one of your answer.

So, therefore so far we have in our answer: n^2 + 3n.

To then find the last part of our answer, we find our term 0. (The term before the first one given, in this case is 6).

So then you do you do your Term 1 = 6, and then take 2 away from it, giving you 4.

So, our final answer should be, n^2 + 3n + 4.

Hope :)

-Emilie Xo this is right and it helps! Xo

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3 years ago
Construct a 98% confidence interval to determine whether there is any difference between the mean drug concentration in tablets
inna [77]

Answer:

Step-by-step explanation:

So, we are given two sites;

Site one: 91.28 , 92.83, 89.35, 91.90 82.85, 94.83, 89.83, 89.00, 84.62, 86.96, 88.32, 91.17, 83.86, 89.74, 92.24, 92.59, 84.21, 89.36, 90.96, 92.85, 89.39, 89.82, 89.91, 92.16, 88.67.

=> The mean = add up all the numbers/ the total numbers (which is 25). = 89.55.

=> The standard deviation = 3.005

SITE TWO: 89.35 86.51 89.04 91.82 93.02 88.32 88.76 89.26 90.36 87.16 91.74 86.12 92.10 83.33 87.61 88.20 92.78 86.35 93.84 91.20 93.44 86.77 83.77 93.19 81.79.

=> The mean= add up all the numbers/ the total numbers (which is 25). = 89.033.

=> Standard deviation = 3.271.

NB: the assumption here is that the variance for both sites are the same.

STEP ONE: DETERMINE THE DEGREE OF FREEDOM AND THE CRITICAL VALUE.

The degree of freedom =( mean of site 1 ) + (mean of site 2) - 2 = (25 + 25) − 2 = 48.

Since the degree of freedom is 48, Recall that the value for alpha given = 0.02. Then, the critical value = 2.407.

STEP TWO: DETERMINE THE STANDARD DEVIATION AND THE STANDARD ERROR FOR BOTH.

Therefore, the standard deviation = √[( 25 - 1) × 3.005^2 + (25 -1) × 3.271^2) ÷ (25 +25 - 2) ] = 3.14.

Also, the standard error = standard deviation × ( √(1/ mean 1 + 1/mean 2) ..

Standard error = 3.14 × [ ✓( 1/25 + 1/25)] = 0.89.

STEP THREE: DETERMINE THE CONFIDENCE INTERVAL.

confidence interval = (89.548 - 89.033 - 2.41 × 0.89, 89.548 - 89.033 + 2.41 × 0.89) = (- 1.62, 2.65).

STEP FOUR: THE HYPOTHESES.

=> THE TWO TAILED TEST.

Jo:μ1​ = μ2​.

Ja: μ1​ ≠ μ2​.

Thus, the rejected region is {t : ∣ t ∣ > 2.7}

As critical value = 2.7 for the degree of freedom which is 48 and α=0.01.

If we do the t - test for this,.we will have;

(89.548 - 89.003)÷ ( standard deviation × √ ( 1/25 + 1/25). = 0.58.

So,from our t - value, is less or equals to the critical value, therefore, the null hypothesis is not rejected.

Also, from the p-value table which gives p=0.565. The p- value is greater than or equal to the alpha value(0.01). therefore, the null hypothesis is not rejected.

We are not going to reject the null hypothesis because the information gathered is not enough.

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