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prisoha [69]
2 years ago
7

PLEAS HELP , I NEED IT RIGHT NOW PLEASE , JUST SAY YES OR NO PLEASE​

Mathematics
1 answer:
Mrac [35]2 years ago
7 0

Answer:

Step-by-step explanation:

a. NO

b. YES

c. YES

d. YES

e. YES

f. NO

g. YES

h. NO

i. NO

j. YES

k. YES

d. YES

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juila has 3 1/2 pounds of dog food.she has to slit it quality among her 7 dogs how much food will each dog receive
azamat
1/2 a pound per dog
3 1/2=3.5lbs
3.5÷7=.5
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3 0
3 years ago
A triangle has vertices at (4,-2), (2,2) and (4,6). What are the vertices of the image of the triangle after applying the transl
Paha777 [63]

I believe it’s D. Hope this helps

4 0
3 years ago
Read 2 more answers
The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
3 years ago
14+-6 what is the answer answer
Irina-Kira [14]

Answer:

the answer is 8. just think of it as subtraction. subtract +6 from +14. then you get the answer for +14+-6.

3 0
3 years ago
Write y=5/8x +6 in standard form using intergers
Art [367]

Answer:

5x - 8y = -48

Step-by-step explanation:

Move 5/8x to the y side to get (-5/8)x + y = 6. Multiply both sides by -8 to get 5x - 8y = -48.

8 0
2 years ago
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