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2 years ago

PLEAS HELP , I NEED IT RIGHT NOW PLEASE , JUST SAY YES OR NO PLEASE

Mathematics

1 answer:

Mrac [35]2 years ago

7 0

Answer:

Step-by-step explanation:

a. NO

b. YES

c. YES

d. YES

e. YES

f. NO

g. YES

h. NO

i. NO

j. YES

k. YES

d. YES

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2 years ago

Read 2 more answers

8/x-5 - 9/x-4 = 5/x^2-9x+20

adelina 88 [10]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2752942

_______________

Solve the equation:

$\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}$

Reduce the fractions at the left side so that they have the same denominator:

$\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}$

Numerators must be equal:

$\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}$

I hope this helps. =)

Tags: <em>rational equation fraction solution algebra</em>

7 0

2 years ago

PLEAS HELP , I NEED IT RIGHT NOW PLEASE , JUST SAY YES OR NO PLEASE​

PLEAS HELP , I NEED IT RIGHT NOW PLEASE , JUST SAY YES OR NO PLEASE