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Sergeeva-Olga [200]
2 years ago
6

A parking garage charges $30 a month plus $0.50 an hour for day time parking. If James had 48 hours worth of day time parking in

April, how much would he have to pay?
Mathematics
1 answer:
Leno4ka [110]2 years ago
3 0
$30+ (0.50*48)=$30+$24=$54 (hope this is correct!)
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The next correct step would be to open the absolute value signs. To do so, the equation would need to be put equal to two values wich both need to be solved to find the correct answers.

Equation 1: x-5=3
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4 years ago
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Shelton Drew a circle with a radius ir 10 centimeters. He than shaded 2 portions of his circle. Find the area of the shaded port
Anton [14]

Answer:

The Area of shaded portion is 314000 cm²

Step-by-step explanation:

Given as :

The circle is drawn with radius = r = 10 cm

Two portion of circle is shaded

∵ two portion is shaded means whole the circle is shaded now

Let The area of shaded portion = A = area of circle

∵ Area of circle = A = π × radius²

where π =  3.14

Or, A = 3.14 × r²

Or, A = 3.14 × (100)²

Or, A = 3.14 × 10000

Or, A = \dfrac{3140000}{100}

I.e A = 314000 cm²

So, The Area of shaded portion = A =  314000 cm²

Hence, The Area of shaded portion is 314000 cm²   Answer

5 0
4 years ago
F(x) = 1/x^2 and g(x) = 1/2x+4<br><br> f[g(x)] = 4x 2 _____
Korolek [52]

Answer:

f[g(x)] = 4x²+1/16

Step-by-step explanation:

We need to put g(x) into f(x).

f[g(x)] = 1/(1/2x+4)²

f[g(x)] = 1/(1/4x²+16) Solve the exponential.

f[g(x)] = 1/(1/4x²+16) Simply the fraction.

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5 0
3 years ago
URGENT<br> I put an answer already but I need a confirmation!
Orlov [11]

Answer:

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4 0
3 years ago
You enter a chess tournament where your probability of winning a game is 0.3 against half the players (call them type 1), 0.4 ag
Doss [256]

The probability of winning is 0.44 .

<u>Step-by-step explanation:</u>

Here it's given that , You enter a chess tournament where your probability of winning a game is 0.3 against half the players (call them type 1), 0.4 against a quarter of the players (call them type 2), and 0.5 against the remaining quarter of the players (call them type 3). You play a game against a randomly chosen opponent. More precisely :

Probability(type1) = 0.3\\Probability(type2) = 0.4\\Probability(type3) = 0.5\\\\Probability(winning) = w

Now, we choose a random opponent and we need to find probability of winning which is possible as :

<u>1. player chosen from type1</u>

<u>2. player chosen from type2</u>

<u>3. player chosen from type3</u>

Combining all cases we get :

⇒ w = type1(1-type2)(1-type3) + (1-type1)type2(1-type3) + (1-type1)(1-type2)type3

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⇒ w = 0.44

∴ The probability of winning is 0.44 .

8 0
3 years ago
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