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choli [55]
3 years ago
6

Dishwashers are on sale for 25% off the original price (d), which can be expressed with the function p(d) = 0.75d. Local taxes a

re an additional 14% of the discounted price, which can be expressed with the function c(p) = 1.14p. Using this information, which of the following represents the final price of a dishwasher with the discount and taxes applied?
c(p) ⋅ p(d) = 0.855pd
c(p) + p(d) = 1.89d
c[p(d)] = 0.855d
d[c(p)] = 1.89p
Mathematics
1 answer:
shutvik [7]3 years ago
8 0

We are given the functions:

<span>P (d) = 0.75 d                                      ---> 1</span>

<span>C (P) = 1.14 P                                      ---> 2</span>

The problem asks us to find for the final price after discount and taxes applied; therefore we have to find the composite function of the two given functions 1 and 2. To solve for composite function of the final price of the dishwasher with the discount and taxes applied, all we have to do is to plug in the value of P (d) with variable d into the equation of C (P). That is:

C (P) = 1.14 (0.75 d)

C (P) = 0.855 d

or

<span>C [P (d)] = 0.855 d</span>

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<h3>Answer:     2500 grams</h3>

============================================

Work Shown:

A = amount of grams of cheese you had originally

B = (2/5)*A = amount of cheese you use up after day 1

C = (3/5)*A = amount of cheese you have left over after day 1

note how B and C add back up to 'A'.

This is because 2/5+3/5 = 5/5 = 1, so,

B+C = (2/5)A+(3/5)A = (2/5+3/5)A = 1*A = A

--------------

D = (2/5)*C = amount of cheese you use up after day 2

E = (3/5)*C = amount of cheese left over after day 2

the variables D and E add up to C

we are told that there are 900 grams of cheese left after day 2, so E = 900

--------------

E = (3/5)*C

(3/5)*C = E

(3/5)*C = 900 ... Plug in E = 900

3C = 900*5 .... multiply both sides by 5

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This means you had 1500 grams of cheese after day 1

-------------

C = (3/5)*A

(3/5)*A = C

(3/5)*A = 1500 ... plug in C = 1500

3A = 1500*5 ... multiply both sides by 5

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A = 7500/3 .... divide both sides by 3

A = 2500

-----------

<h3>You started off with 2500 grams of cheese.</h3>

After day 1, you use up (2/5)*2500 = 1000 grams of cheese and have 2500-1000 = 1500 grams left over.

After day 2, you use up (2/5)*1500 = 600 grams of cheese and have 1500-600 = 900 grams left over.

The answer is confirmed.

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