PLEASE HELP, 40 POINTS!!!!!!!!!!!!!!!!!!!

What is 612.0÷0.06 please help me

erik [133]

Answer:

10,200

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The frist brand is 30% and the second on is 55% in order to obtain 30 gallons of mixture that contains 35% how many gallons of e

snow_tiger [21]

yeet

first brand quantity is x

2nd brand quantity is y

x+y=30

0.3x+0.55y=0.35(30) or 0.3x+0.55y=10.5

solve for x and y

multiply first equation by -0.3

-0.3x-0.3y=-9

add to 2nd equation

0.3x-0.3y=-9

0.3x+0.55y=10.5 +

0x+0.25y=1.5

0.25y=1.5

divide both sides by 0.25

y=6

sub back

x+y=30

x+6=30

x=24

you need 24 gallons of the first brand and 6 gallons of the 2nd brand

4 0

2 years ago

Read 2 more answers

Jeremy drew a polygon with four right angles and four sides with the same length. Name all the polygons that he could have drawn

sergejj [24]

Square.

A square is a rectangle, so rectangle.

A rectangle is a parallelogram, so parallelogram.

Equilateral.

Also Rhombus.

(I think there may be others but these are the few I know)

8 0

2 years ago

11. What is 6:12 in simplest form? A. 2:1 B. 1:2 C. 12:6 D.2

Artyom0805 [142]

The answer is B 1:2. I hope you get it right

4 0

2 years ago

Please help me!! 100 points!!

Lyrx [107]

Part A.

We could take, for example:

$\begin{cases}x\geq-3\\y\geq3\end{cases}$

For x ≥ -3 we have vertical line (x-intercept = -3) and shaded region on the right side of the line.
For y ≥ 3 we have horizontal line (y-intercept = 3) and shaded region above that line.

Part B.

Simply, substitute x and y coordinates of D and E to the system of inequalities from part A, and check if its is true, what we get.

$D=(-2,4)\\\\\begin{cases}x\geq-3\\y\geq3\end{cases}\quad\implies\quad\begin{cases}-2\geq-3\qquad\text{True}\\4\geq3\qquad\text{True}\end{cases}$

so point D is a solution,

$E=(2,4)\\\\\begin{cases}x\geq-3\\y\geq3\end{cases}\quad\implies\quad\begin{cases}2\geq-3\qquad\text{True}\\4\geq3\qquad\text{True}\end{cases}$

and point E is also a solution to our system of inequalities.

Part C.

There are two ways we could do that. First is the same as in part B. We substitute x and y coordinates of each school and check if inequality is true or false:

$A=(-5,5)\\\\y\ \textless \ 3x-3\quad\implies\quad5\ \textless \ 3\cdot(-5)-3\quad\implies\quad5\ \textless \ -18\quad\text{False}\\\\\\
B=(-4,-2)\\\\y\ \textless \ 3x-3\quad\implies\quad-2\ \textless \ 3\cdot(-4)-3\quad\implies\quad-2\ \textless \ -15\quad\text{False}\\\\\\
C=(2,1)\\\\y\ \textless \ 3x-3\quad\implies\quad1\ \textless \ 3\cdot2-3\quad\implies\quad1\ \textless \ 3\quad\text{True}\\\\\\
D=(-2,4)\\\\y\ \textless \ 3x-3\quad\implies\quad4\ \textless \ 3\cdot(-2)-3\quad\implies\quad4\ \textless \ -9\quad\text{False}\\\\\\
E=(2,4)\\\\y\ \textless \ 3x-3\quad\implies\quad4\ \textless \ 3\cdot2-3\quad\implies\quad4\ \textless \ 3\quad\text{False}\\\\\\$

$F=(3,-4)\\\\y\ \textless \ 3x-3\quad\implies\quad-4\ \textless \ 3\cdot3-3\quad\implies\quad-4\ \textless \ 6\quad\text{True}\\\\\\$

So Timothy can attend schools C and F.

We can also draw a graph of that inequality (pic 2).

8 0

2 years ago

Read 2 more answers