Answer:
See explanation
Step-by-step explanation:
Consider triangles ACM and BCM. In these triangles,
- given;
- definition of perpendicular lines CM and AB;
- reflexive property.
So,
by ASA postulate (if one side and two angles adjacent to this side of one triangle are congruent to one side and two angles adjacent to this side of another triangle, then two triangles are congruent).
Two-column proof:
Statement Reason
1. Given
2. 
Given
3. Definition of perpendicular lines CM and AB
4. Reflexive property
5. ASA postulate
Assume you mean 3x^2 when you typed the question.
3x^2+14x+16=0
(3x+8)(x+2)=0
x=-8/3 or -2
We need an equation for this, theres no 'formula' for doing this (ignoring the quadratic formula, as that is a long-winded way of factorising a quadratic equation)
Answer:
here
Step-by-step explanation:
it is basically a sector , use the area formula i.e.
[(theta)/360]*πr^2
Step-by-step explanation:
log <base a> b = x
means
a^x = b
So
3^2 = x^2+7x+21
x^2 + 7x + 21 - 9 = 0
x^2 + 7x + 12 = 0
(x+3)(x+4)
x = -3 or -4
