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3 years ago

Can you help me with these two?

Mathematics

2 answers:

bixtya [17]3 years ago

6 0

12. ((x+3) (x-1)) / (x-3)
13. 8m^7-10m^5

timofeeve [1]3 years ago

3 0

For number 13 it is the fourth one since you can break it apart as (8m^7)/(2m^3) then subtract (10m^5)/(2m^3)

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sammi is trying to wrap a gift for her brother. the gift fits into a cube-shaped box with a side length of 9 inches. how many sq

Flauer [41]

Answer:

$A=486\ \text{inches}^2$

Step-by-step explanation:

The area of a cube shaped box is given by :

$A=6s^2$

Where

s is the side length and A is the surface area

We have, s = 9 inches

So,

$A=6\times (9)^2\\\\A=486\ \text{inches}^2$

So, the required area is $486\ \text{inches}^2$ .

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2 years ago

How to write 3,028,002 In Word Form

allsm [11]

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3 years ago

Read 2 more answers

Can i please have help with number 6

Allisa [31]

Length of the diameter = sqrt ( (-12- (-8)^2) +(2-0)^2) )
= sqrt (16 + 4) = sqrt20
so radius = sqrt 20 / 2 = sqrt5
so r^2 = 5

Center of the circle = coordinates of the midpoint of the diameter =

-8-12/2 , 2-0 / 2 = (-10, 1)

(x - a)^2 + (y - b)^2 = r^2 is general form of a circle so here the circle is:_

(x + 10)^2 + (y - 1)^2 = 5 Answer

Its B

7 0

3 years ago

F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa

DerKrebs [107]

a. Parameterize $C$ by

$\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath$

with $0\le t\le1$ .

b/c. The line integral of $\vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath$ over $C$ is

$\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt$

$=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt$

$=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt$

$=\displaystyle10\int_0^1\mathrm dt=\boxed{10}$

d. Notice that we can write the line integral as

$\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)$

By Green's theorem, the line integral is equivalent to

$\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy$

where $D$ is the triangle bounded by $C$ , and this integral is simply twice the area of $D$ . $D$ is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

4 0

3 years ago

Plzzzzzzzzzzz help me

Serjik [45]

I think the answer is 49 cookies

8 0

3 years ago