A there are no real zeros
using the discriminant b² - 4ac to determine the nature of the zeros
for y = x² + 4x + 5 ( with a = 1, b = 4 and c = 5 )
• If b² - 4ac > 0 there are 2 real and distinct zeros
• If b² - 4ac = 0 there is a real and equal zero
• If b² - 4ac < 0 there are no real zeros
b² - 4ac = 16 - 20 = - 4
Since discriminant < 0 there are no real zeros
Answer:
Slope: 0
y-intercept: (0,-1)
Step-by-step explanation:
Step-by-step explanation:
3(x+4) ≤ 36
3x + 12 ≤ 36
3x ≤ 24
x ≤ 8
Number 1 is 15 number 2 is 9x3=27 and number 3 is 15 and number 4 is 5x7=35 number number 6 is 5 number 7 is 11 and that is about all i know hope this helps
