***SUPER HARD QUESTION THAT I CAN'T SOLVE, HOMEWORK IS DUE TOMMOROW! HELP!!!

The domain of both

Margarita [4]

Answer:

The domain of function $h(x)$ is set of all real numbers.

Domain: (-∞,∞)

Step-by-step explanation:

Given:

$f(x)=x-6$

$g(x)=x+6$

the domain of both the above functions is all real number.

To find domain of :

$h(x)=f(x)g(x)$

Substituting functions $f(x)$ and $g(x)$ to find $h(x)$

$h(x)=(x-6)(x+6)$

The product can be written as difference of squares. $[a^2-b^2=(a+b)(a-b)]$

∴ $h(x)=x^2-36$

The degree of the function $h(x)$ is 2 as the exponent of leading term $x^2$ is 2. Thus its a quadratic equation.

For any quadratic equation the domain is set of all real numbers.

So Domain of $h(x)$ is (-∞,∞)

7 0

3 years ago

Simplify square root of 1008 ( V` Represents the square root sign.)

Alexus [3.1K]

So first factor it
1008=2*2*2*2*3*3*7
group them in similar pairs
1008=(2*2)(2*2)(3*3)*7
now remember we can do
$\sqrt{xy}= \sqrt{x} \sqrt{y}$ so
$\sqrt{1008}= (\sqrt{2*2}) (\sqrt{2*2}) (\sqrt{3*3}) (\sqrt{7})$ =
2*2*3* $\sqrt{7}$ =
12√7

the answer is B

5 0

2 years ago

Enter a range of values of x

igomit [66]

Answer:

$-5$ .

Step-by-step explanation:

We know that if two corresponding sides of two triangles are equal, then third sides of the triangles depend on angle between equal sides.

Angle opposite to larger side is larger.

Since, 14 < 15, therefore

$2x+10$

$2x$

$x$ ...(1)

We know that, angle can not not negative.

$2x+10>0$

$2x>-10$

$x>-5$ ...(2)

From (1) and (2), we get

$-5$

Therefore, the range of values of x is $-5$ .

4 0

2 years ago

Calculating cos-1 ( help is gladly appreciated :) )

Alekssandra [29.7K]

Answer:

$\frac{3\pi}{4}$

(Assuming you want your answer in radians)

If you want the answer in degrees just multiply your answer in radians by $\frac{180^\circ}{\pi}$ giving you:

$\frac{3\pi}{4} \cdot \frac{180^\circ}{\pi}=\frac{3(180)}{4}=135^{\circ}$ .

We can do this since $\pi \text{ rad }=180^\circ$ (half the circumference of the unit circle is equivalent to 180 degree rotation).

Step-by-step explanation:

$\cos^{-1}(x)$ is going to output an angle measurement in $[0,\pi]$ .

So we are looking to solve the following equation in that interval:

$\cos(x)=-\frac{\sqrt{2}}{2}$ .

This happens in the second quadrant on the given interval.

The solution to the equation is $\frac{3\pi}{4}$ .

So we are saying that $\cos(\frac{3\pi}{4})=\frac{-\sqrt{2}}{2}$ implies $\cos^{-1}(\frac{-\sqrt{2}}{2})=\frac{3\pi}{4}$ since $\frac{3\pi}{4} \in [0,\pi]$ .

Answer is $\frac{3\pi}{4}$ .

4 0

2 years ago

If 2 ounces is 240 calories then what is 2/3 ounces

Alex17521 [72]

If 2 ounces = 240 calories

1 ounce = 120 calories
So 2/3 ounces = (2/3) * 120
= 80 calories

4 0

3 years ago

***SUPER HARD QUESTION THAT I CAN'T SOLVE, HOMEWORK IS DUE TOMMOROW! HELP!!!​

***SUPER HARD QUESTION THAT I CAN'T SOLVE, HOMEWORK IS DUE TOMMOROW! HELP!!!