Question

Problem number 26 of the Rhind Papyrus says: Find a quantity such that when it is added to StartFraction 1 Over 4 EndFraction of itself the result is a 15. The modern day equation that models this problem is x plus StartFraction 1 over 4 EndFraction x equals 15.. What is the solution to the equation? x = 10 x = 12 x = 15 x = 30

Answer 1

Answer:

B

Step-by-step explanation:

2020 edge

Answer 2

Answer:

$x = 12$

Step-by-step explanation:

x = the quantity to find

This quantity added to ¼ of itself gives 15.

Thus, this problem can be represented as given above:

$x + \frac{1}{4}x = 15$

Solve for x

$x + \frac{x}{4} = 15$

$\frac{4x + x}{4} = 15$

$\frac{5x}{4} = 15$

Multiply both sides by 4

$\frac{5x}{4}*4 = 15*4$

$5x = 60$

Divide both sides by 5

$\frac{5x}{5} = \frac{60}{5}$

$x = 12$