Answer:
A money market account paying 3.5% interest, renewable for three-month commitments.
Answer:


Step-by-step explanation:
Given




Required
The number of each coin
The total coins can be represented as:


So, the worth of the coin is:

The equations to solve are:


Make d the subject in: 

Substitute
in 


Collect like terms


Solve for q


Substitute
in 


So:


Answer:
- dimensions: 12 ft by 5 ft
- area: 60 ft²
Step-by-step explanation:
Let x represent the shorter dimension in feet. Then the longer one is x+7 and the Pythagorean theorem tells us the relation of these to the diagonal is ...
x² + (x+7)² = 13²
2x² +14x + 49 = 169 . . . . eliminate parentheses
x² +7x -60 = 0 . . . . . subtract 169 and divide by 2
(x +12)(x -5) = 0 . . . . factor the equation
x = -12 or +5 . . . . . . . only the positive value of x is useful here.
The short dimension is 5 ft, so the long dimension is 12 ft. The area is their product, 60 ft².
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<em>Comment on finding the area</em>
The quadratic equation above can be rearranged and factored as ...
x(x +7) = 60
Since the dimensions of the garden are x and (x+7), this product is the garden's area. This equation tells us the area is 60. We don't actually have to find the dimensions.
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
Population mean (μ) = 2.55
Population standard deviation (σ) = 0.5
Sample size (n) = 30
Sample mean (x) = 2.76
α = 0.05
STEP 1:
Stress score in general executive (s1)
Stress score in exercising executive (s2)
Null : s1 = s2
Alternative : s1 < s2
STEP 2:
Shape of distribution = normal
Population mean (μ) = 2.55
Population standard deviation (σ) = 0.5
Sample size (n) = 30
Sample mean (x) = 2.76
α = 0.05
Decision rule :
α = 0.05 which corresponds to a t score (t0) ;
df = n - 1 = 30 - 1= 30 at 0.05 = 1.699
If :
(Test statistic (t) > t0) ; reject the Null
(right tailed test)
Test statistic (t) :
(x - μ) / (σ/√n)
(2.76 - 2.55) / (0.5/√30)
0.21 / 0.0913
= 2.30
t > t0
2.30 > 1.699
t is more extreme than t0
Hence, reject the null at α = 0.05