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Mariana [72]
3 years ago
6

Which of the following statements is true? When rolling a fair number cube - ____________ A) the theoretical probability is alwa

ys greater than the experimental probability. B) the theoretical probability is always less than the experimental probability. C) the more times the cube is rolled the closer the experimental probability gets to theoretical probability. D) the number 7 will appear more than the
Mathematics
2 answers:
tiny-mole [99]3 years ago
7 0
I believe that the answer is C because lets say you decide that the cube will roll on 1 six times. if you roll the cube 6 times, then there is a 1/6 probability of the cube landing on 1, but the more times you roll the cube, the more chances there will be of the number landing that many times as you theorized 
Softa [21]3 years ago
3 0
The answer is c hope that helps
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X - 2y = 3<br> 5x + 3y = 2<br> The lines whose equations are shown intersect at which point?
Lady_Fox [76]

The point of intersection of the two lines is at (1,-1)

<h3>System of equation</h3>

The given system of expression is shown below

x - 2y = 3

5x + 3y = 2

The solution to the system of equation is the point of intersection

From equation 1

x = 3 + 2y

Substitute into 2

5(3+2y) + 3y = 2

15 +10y + 3y = 2

13y = -13

y = -1

Substitute y = -1 into 3

x = 3 + 2y

x = 3+(-2)

x = 1

Hence the point of intersection of the two lines is at (1,-1)

Learn more on system of equation here: brainly.com/question/25976025

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8 0
2 years ago
Can I get help on this math problem makes makes no sense
lana66690 [7]
(2,-1) The intersecting point is the point where the two lines meet.
5 0
3 years ago
X² – 2x - 15 / x² - 6x+5
Nuetrik [128]

Answer:

all work is pictured/shown

7 0
3 years ago
Can anyone help me out in my homework. I would love to talk about these problems ​
katen-ka-za [31]

Step-by-step explanation:

(b) If F_G = m_1g, then

m_1g = G\dfrac{m_1m_2}{r^2}

Note that m_1 cancel out so we get

g = G\dfrac{m_2}{r^2}

Solving for m_2, we get

m_2 = \dfrac{gr^2}{G}

(c) I'm not sure what the problem is asking for but here goes. As r doubles, F_G becomes

F_G = G\dfrac{m_1m_2}{(2r)^2} = \dfrac{1}{4}\left(G\dfrac{m_1m_2}{r^2}\right)

5 0
3 years ago
Simplify.Your answer should contain only positive exponents.
zhannawk [14.2K]

Step-by-step explanation:

1) r^3r^3

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

=r^{3+3}

=r^6

2) 3k^3k^3

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

=3k^{3+3}

=3k^6

3) \left(3b^2\right)^3

\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n

=3^3\left(b^2\right)^3

=27\left(b^2\right)^3

=27b^6

4) \left(2m^3\right)^3

\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n

=2^3\left(m^3\right)^3

=8\left(m^3\right)^3

=8m^{3\cdot \:3}

=8m^9

5) \frac{3r^3}{r^2}

\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}

=3r^{3-2}

=3r^1

=3r

3 0
3 years ago
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