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Natasha_Volkova [10]
3 years ago
6

1.Consider the system of equations. x-5y=2

Mathematics
1 answer:
JulijaS [17]3 years ago
8 0
1.Consider the system of equations. x-5y=2
3x-10y=11

(a) Jamar rewrote the first equation as –2x + 10y = –4. What justification did he have for doing this?

(b)Jamar combined the equation in Part (a) with the second equation in the system to get x = 7. Explain Jamar’s reasoning.

(c) What is the solution of the system? (d) How do you know, without graphing, that the graph of 4x – 15y = 13 passes through the point whose coordinates are the solution of the system?

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Convert 5 square root of a into exponential form?
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Answer:

The answer is:  " 5a^\frac{1}{2} "  .

_____________________________________________

Step-by-step explanation:

______________________________________________

We are asked to convert "5 square root of a"  ;  into "exponential form".

Note that "5 square root of a" ;

             or;  " 5 root a " ;

means:    " 5 times the {square root of the variable, "a" };

      or :    " 5 multiplied by the {square root of the variable, "a" }.

_______________________________________________

This can be written as:   " 5\sqrt{a} " .

_______________________________________________

<u>Note the following property of exponents</u>:

\sqrt[n]{a^m} = (\sqrt[n]{a})^m = a^m^n .

_____________________________________________

So;  to write:  " √a "  ;  <u> </u><em><u>as an exponent</u></em><u> </u> :

______________________________________________

<u>Note</u>:  

" \sqrt{a}  = \sqrt[2]{a} =   \sqrt[2]{a^1} = (\sqrt[2]{a})^1 =  a^\frac{1}{2} " .

_______________________________________________

<u>So</u>:

" \sqrt{a}  =  a^\frac{1}{2} "  ;

_______________________________________________

<u>And</u>:

________________________________________________

" 5\sqrt{a}  =  5a^\frac{1}{2} " .

________________________________________________

   →   The answer is:  " 5a^\frac{1}{2} " .

________________________________________________

Hope this helps!

   Best wishes in your academic endeavors

           — and within the "Brainly" community!

________________________________________________

6 0
3 years ago
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