1.Consider the system of equations. x-5y=2
1 answer:
1.Consider the system of equations. x-5y=2
3x-10y=11
(a) Jamar rewrote the first equation as –2x + 10y = –4. What justification did he have for doing this?
(b)Jamar combined the equation in Part (a) with the second equation in the system to get x = 7. Explain Jamar’s reasoning.
(c) What is the solution of the system? (d) How do you know, without graphing, that the graph of 4x – 15y = 13 passes through the point whose coordinates are the solution of the system?
3x-10y=11
(a) Jamar rewrote the first equation as –2x + 10y = –4. What justification did he have for doing this?
(b)Jamar combined the equation in Part (a) with the second equation in the system to get x = 7. Explain Jamar’s reasoning.
(c) What is the solution of the system? (d) How do you know, without graphing, that the graph of 4x – 15y = 13 passes through the point whose coordinates are the solution of the system?
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Answer:
The length of EG is 58 units
Step-by-step explanation:
The midpoint of a segment divides it into two equal part
Let us use this rule to solve our question
∵ E, F, and G are collinear points
∵ Point F is the midpoint of segment EG
→ That means F divides EG into 2 equal segments EF and FG
∴ EF = FG
∵ EF = 5x + 9
∵ FG = 3x + 17
→ Equate them
∴ 5x + 9 = 3x + 17
→ Subtract 3x from both sides
∵ 5x - 3x + 9 = 3x - 3x + 17
∴ 2x + 9 = 17
→ Subtract 9 from both sides
∴ 2x + 9 - 9 = 17 - 9
∴ 2x = 8
→ Divide both sides by 2 to find x
∵
∴ x = 4
→ Substitute x by 4 in EF and FG to find their lengths
∵ EF = 5(4) + 9 = 20 + 9 = 29
∵ FG = 3(4) + 17 = 12 = 17 = 29
∵ EG = EF + FG
∴ EG = 29 + 29 = 58
∴ The length of EG is 58 units