There are different kinds of attributes. The option that is not represent an attribute of the function f(x) = |x| is that the graph has a line of symmetry at y = 0.
Note that:
f(x) = IxI
IxI = x if x ≥ 0
IxI = -x if x ≤ 0.
<h3>Why is the statement false</h3><h3 />
The graph has a line of symmetry at y = 0." is false because the real line of symmetry is at x = 0, y = 0 is in line with the x-axis. Therefore as the graph opens up, we would not be able to have symmetry on any line parallel to the x-axis.
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Answer:
Steve Jobs
Explanation:
Steve Jobs, Ronald Wayne and Steve Wozniak.
Equity implies the amount of shares owned by a partner in business
A statement of changes in partner's equity should not include cash
<h3>How to determine the exempted content</h3>
In finance, a statement of equity must include all of the following
- Contributed capital by each partner
- Retained earnings by each partner
- Accumulated comprehensive incomes
However, the statement of changes in partner's equity should not include cash
Hence, the statement that answers the question is cash
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The calculated pH of the solutions are given below:
- The pH of the solution after 14.0 ml of base is added to it is calculated as 1.45.
- The pH of the solution after 19.8 ml of base is added to it is calculated as 3.0
- The pH of the solution after 20.0 ml of base is added to it is calculated as 7.
<h3>What is pH?</h3>
This is the level of acidity or alkalinity of an aqueous solution. The pH of a substances tells if its an acid, base or neutral.
HBr and NaOH while in water would dissociate and they would become H+ and OH- respectively.
Mol of HBr = Mol * Vol
= 0.200 * 20mL
= 4 mmol
A. Moles of NaOH added
= 0.2 X 14
= 2.8 mmol
Moles of H+ that did not react
= 4 - 2.8
= 1.2 mmol
1.2/1000 = 0.0012 moles
Total volume = 20 + 14
= 34 mL to litres
= 0.034 L
Molarity of H+ = 0.0012 / 0.034L
= 0.035 M
-log[0.035] = 1.45
The pH of the solution is 1.45
B. NaOH added = 19.8 * 0.2 =
3.96 mmoles
The unreacted solution
= 4.0 - 3.96
= 0.04 mmol
0.04/1000 = 0.00004 moles
Total volume = 20 + 19.8
= 39.8mL
Converted to litres = 0.0398L
Molarity = 0.00004 / 0.0398L
= 0.001
-log(0.001) = 3.0
The ph Is therefore 3.0
C. Moles of NaOH added = 0.2*20mL = 4mmol
All the H+ are going to be consumed here. This would result into a neutral solution pH = 7
<u>Complete question:</u>
20.0 mL sample of 0.200 M HBr solution is titrated with 0.200 M NaOH solution. Calculate the PH of the solution after the following volumes of base have been added.
A. 14.0 mL
B. 19.8 mL
C. 20.0 mL
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