The initial value of 100 that doubles over each interval.
without the answer choices, I can only describe it and give you an example of the graph.
I'm assuming the function is 100*(2)^x because if it is as listed it would be a quadratic function with a vertical stretch of 100.
Determine which value is equivalent to | f ( i ) | if the function is: f ( x ) = 1 - x. We know that for the complex number: z = a + b i , the absolute value is: | z | = sqrt( a^2 + b^2 ). In this case: | f ( i )| = | 1 - i |. So: a = 1, b = - 1. | f ( i ) | = sqrt ( 1^2 + ( - 1 )^2) = sqrt ( 1 + 1 ) = sqrt ( 2 ). ANSWER IS C. sqrt( 2 )
Answer:
here is the answer to your question
Answer:
17/300.
Step-by-step explanation:
17/300 students have a dog.
21.4
it’s an equal triangle so you do
2 x 3 = 6
6 x 3 = 18
2(1 x 1.7) = 3.4
18 + 3.4 = 21.4