Answer: 
Step-by-step explanation:
Answer:767600640
Step-by-step explanation: If 720 equals x, you multiply 128 by 720, and multiply the answer by 8,329.
Answer:
C) (-3, -1)
Step-by-step explanation:
y = 5/3x + 4
When x = 0, y = 4
When y = 0, x = -2.4
graph the points: (0, 4) and (-2.4, 0)
y = -2/3x - 3
When x = 0, y = -3
When y = 0, x = -4.5
graph the points: (0, -3) and (-4.5, 0)
The lines will cross at point: (-3, -1)
First picture)
I: 5x+2y=-4
II: -3x+2y=12
add I+(-1*II):
5x+2y-(-3x+2y)=-4-12
8x=-16
x=-2
insert x=-2 into I:
5*(-2)+2y=-4
-10+2y=-4
2y=6
y=3
(-2,3)
question 6)
I: totalcost=115=3*childs+5*adults
II: 33=adults+childs
33-adults=childs
insert childs into I:
115=3*(33-adults)+5*adults
115=99-3*adults+5*adults
16=2*adults
8=adults
insert adults into II:
33-8=childs
25=childs
so it's the last option
question 7)
a) y<6 and y>2 can also be written as 2<y<6, so solution 3 exist for example
b) y>6 and y>2 can also be written as 2<6<y, so solution 7 exist for example
c) y<6 and y<2 inverse of b: y<2<6, so for example 1
d) y>6 and y<2: y<2<6<y, this is impossible as y can be only either bigger or smaller than 2 or 6
so it's the last option
question 8)
I: x+y=12
II: x-y=6
subtract: I-II:
x+y-(x-y)=12-6
2y=6
y=3
insert y into I:
x+3=12
x=9
(9,3)
question 9)
I: x+y=6
II: x=y+5
if you take the x=y+5 definition of II and substitute it into I:
(y+5)+y=6
which is the second option :)
Answer:
m∠1= 79
Step-by-step explanation:
What we have here is two vertical lines and one intersecting point.
The m∠1 and m∠6 are vertical angles, which means that they equal to each other. So, the equation would be: 6x+25= 10x-11.
Step 1- Subtract 6x to both sides.
6x+25= 10x-11
-6x -6x
25= 4x-11
Step 2- Add 11 to both sides.
25= 4x-11
+11 +11
36= 4x
Step 3- Divide both sides by 4.
<u>36</u>= <u>4x</u>
4 4
x= 9
Now that we know the value of the variable x, substitute it into the equation for m∠1.
m∠1= 10(9)-11
m∠1= 90-11
m∠= 79
<u>Check </u>
m∠6= 6(9)+25
m∠6= 54+25
m∠6= 79
Since m∠1 and m∠6 are vertical angles, they should equal each other.
