A. 5x10 to the third power
2 answers:
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Answer:
Probability that a smoker has lung disease = 0.2132
Step-by-step explanation:
Let L = event that % of population having lung disease, P(L) = 0.07
So,% of population not having lung disease, P(L') = 1 - P(L) = 1 - 0.07 = 0.93
S = event that person is smoker
% of population that are smokers given they are having lung disease, P(S/L) = 0.90
% of population that are smokers given they are not having lung disease, P(S/L') = 0.25
We know that, conditional probability formula is given by;
P(S/L) =
= P(S/L) * P(L)
= 0.90 * 0.07 = 0.063
So, = 0.063 .
Now, probability that a smoker has lung disease is given by = P(L/S)
P(L/S) =
P(S) = P(S/L) * P(L) + P(S/L') * P(L')
= 0.90 * 0.07 + 0.25 * 0.93 = 0.2955
Therefore, P(L/S) = = 0.2132
Hence, probability that a smoker has lung disease is 0.2132 .
Answer:
Step-by-step explanation:
We are given that:
Where both A and B are positive acute angles.
And we want to find he value of sin(A-B).
Using the first ratio, we can conclude that the opposite side is 35 and the adjacent side is 12.
Then by the Pythagorean Theorem, the hypotenuse is:
Using the second ratio, we can likewise conclude that the opposite side is 20 and the hypotenuse is 29.
Then by the Pythagorean Theorem, the adjacent is:
Therefore, we can conclude that:
So, for A, the adjacent is 12, opposite is 35, and the hypotenuse is 37.
For B, the adjacent is 21, opposite is 20, and the hypotenuse is 29.
We can rewrite sin(A-B) as:
Using the above conclusions, this yields: (Note that since A and B are positive acute angles, all resulting ratios will be positive.)
Evaluate:
Using the z-table, the probability that a student taking this test will finish in 100 minutes or less is 0.0824 or 8.24%.
For a normally distributed set of data, given the mean and standard deviation, the probability can be determined by solving the z-score and using the z-table.
First, solve for the z-score using the formula below.
z-score = (x – μ) / σ
where x = individual data value = 100
μ = mean = 125
σ = standard deviation = 18
z-score = (100 – 125) / 18
z-score = (-25) / 18
z-score = -1.39
Find the probability that corresponds to the z-score in the z-table. (see attached images)
-1.39 - (-1.3) : -1.4 - (-1.3) = x - 0.0968 : 0.0808 - 0.0968
-0.09 : -0.1 = x - 0.0968 : -0.016
x - 0.0968 = -0.09(-0.016)/-0.1
x = -0.0144 + 0.0968
x = 0.0824
x = 0.0824
Hence, the probability that a student taking this test will finish in 100 minutes or less is 0.0824 or 8.24%.
Learn more about probability here: brainly.com/question/26822684
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