The objectives of Accenture's e-stewards program are:
- Its goals to provide a more sustainable and responsible recycling solution to electronic waste (e-waste) problem
- Right handling of electronic waste and no more dumping of electronic waste in poor countries
- No exportation of harmful electronic wastes
- A shift to reuse and resale, repair, republish and re-manufacture.
- E-waste encompasses all waste of electrical and electronic equipment that are often disposed with or without the intent of reuse. is disposed via incineration, reuse, recycling etc.
- e-Stewards is simply known as a form of certification to an organisation, company or recycling business gotten from the international non-profit environmental group.
Conclusively, we can say that the objectives of Accenture's e-stewards program are:
- Its goals to provide a more sustainable and responsible recycling solution to electronic waste (e-waste) problem
- Right handling of electronic waste and no more dumping of electronic waste in poor countries
- No exportation of harmful electronic wastes
- A shift to reuse and resale, repair, republish and re-manufacture.
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brainly.com/question/24828549
The minimum number of comparisons to find the smallest number from 5 integers is 4.
<h3>How to find the Smallest Integer?</h3>
Let the five numbers be a,b,c,d and e.
Let s be an integer
Comparison 1:
a and b will be compared first and the smaller number of them will be equal to s
Comparison 2:
Now, a smaller number between a and b that is s will be compared with c. Similarly, the smaller number of both numbers will be taken as s in the next comparison.
Comparison 3:
Likewise, s and d will be compared and a smaller number will be taken as s for the next comparison
Comparison 4:
Likewise, s and e will be compared and a smaller number will be taken as s for the next comparison.
After 4th comparison, s will be equal to smallest number of 5 integers.
Thus;
Total comparisons = 4
Therefore, the minimum number of comparisons to find the smallest number from 5 integers is 4.
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The answer is c, hope this helps