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Elina [12.6K]
3 years ago
15

1 2 3 or 4 pls help me

Mathematics
2 answers:
Harrizon [31]3 years ago
8 0
It would be 2. The y intercept is on 5 and it goes five down and two right which is -5/2 so it would be y = -5/2x + 5
adell [148]3 years ago
5 0

Answer:

numero 3

Step-by-step explanation:

because the line crosses the 5 on the y axis and when you count it from the 5 to the 2 it would be -2/5.

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In a cross country marathon jack and ted ren a total of 81 kn. Ted ran 5kn farther than jack how far did each of them run?
kotegsom [21]

Answer:

Jack ran 38 km and Ted ran 43 km.

Step-by-step explanation:

Let Jack’s displacement be x

x + (x+5) = 81

2x + 5 = 81\\2x = 76

x = 38 km

x+5 = 38 + 5\\x+5 = 43km\\

3 0
4 years ago
a rectangular prism is 11 3/5 meters long ,9 meters wide ,and 12 1/2 meters high. what is the volume,in cubic meters,of the pris
Katen [24]
The volume of this prism is 
V=l*w*h
rewrite the mixed number as fractions
V= 11 3/5* 9* 12 1/2=
V= 58/5 *9/1* 24/2
V=58*9*24/5*2
V=12528/10=1252 8/10 m^3
or
V=1252.80m^3

4 0
3 years ago
One number is 3 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 500,
Likurg_2 [28]
<span>Let the first number be x.
Then the second number is 3x.
Then the third number is (x+100).
Sum of the numbers=500

x+3x+(x+100)=500</span>
<span>4x+(x+100)-500=0
</span><span>5x=400</span>
<span>x=80
</span><span>The first number is 80.
The second number is 240.
The third number is 180.

We can check by adding all three of those numbers together: 80+240+180 = 500
</span>
Hope this helps! If you have any questions just ask!
8 0
3 years ago
Is 53.33/3=17.776666
Furkat [3]
Yes, <span>53.33/3=17.776666</span>
5 0
3 years ago
Read 2 more answers
What are the coordinates of the vertex of the function f(x)=x^2+10x−3? (–5, –28) (–5, 28) (5, –28) (5, 28)
polet [3.4K]

Answer:

(-5,-28)

Step-by-step explanation:

Given

f(x)=x^2+10x - 3

Required

Find the coordinates of the vertex

Given that the function is a quadratic function;

The general form of a quadratic function is

f(x)= ax^2+bx +c

By comparison;

a = 1\ b = 10\ and\ c = -10

To calculate the coordinates of the vertex;

we start by calculating the x-coordinate;

x = \frac{-b}{2a}

Substitute 10 for b and 1 for a

x = \frac{-10}{2*1}

x = \frac{-10}{2}

x = -5

Substitute x = -5 in the given function;

y=x^2+10x - 3

y=(-5)^2+10*-5 - 3

y=25-50 - 3

y=-28

<em>Hence, the coordinates of the vertex is (-5,-28)</em>

6 0
4 years ago
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