Here's how you solve this. So, x+y=2, right? Let's isolate x. x+y-y=2-y. x=2-y. NOW, if x=2-y, in 3x+2y=5, we can REPLACE x with 2-y and use it to solve for y! 3x+2y=5. 3(2-y)+2y=5. (3*2)+(3*-y)+2y=5. 6+(-3y)+2y=5. 6+(-y)=5. 6+(-y)-6=5-6. -y=-1. -y/-1=-1/-1. y=1.
So, if y=1, we can substitute that back into either equation--but let's go with the easier one, x+y=2. x+1=2. x+1-1=2-1. x=1. 1+1=2, so that works; let's check the other equation. 3(1)+2(1)=5. 3+2=5. 5=5. That's correct!
Answer: x=1, y=1
Answer:
Going from left to right:
1.) Yes
2.) No
3.) Yes
4.) No
5.) No
6.) Yes
7.) No
8.) No
9.) Yes
10.) No
11.) Yes
12.) Yes
13.) No
14.) Yes
15.) Yes
16.) No
Step-by-step explanation:
Functions cannot have any repeating x-coordinates.
Hello,
Your sequence is arithmetic.
10.5-9=1.5
9-7.5=1.5
7.5-6=1.5
6-4.5=3
4.5-3=1.5
3-1.5=1.5
1.5-1.5=0
...
f(x)=f(n-1)-1.5 is the iterative rule.
f(1)=10.5
f(2)=10.5-1.5=9
f(3)=10.5-2*1.5=7.5
f(4)=10.5-3*1.5=6
...
f(n)=10.5-1.5*(n-1) is the general form.
Maybe it's no. 1 bcz WX=YZ.
Answer:
1. (-3,-11),(-2,-8),(-1,-5),(0,-2)(1,1)(2,4) (3,7)
2 (-3,5),(-2,0),(-1,-3), (0,-4),(1,-3),(2,0),(3,5)
