<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
Answer:
r17 is that a mistake or actually the number?
Let us assume the gas bill of Paul in February = x dollars
Then
Electric bill of Paul for the month of February = (x/2) + 3
Amount of Electricity bill of Paul for the month of February = $92
then we can write the equation as
(x/2) + 3 = 92
x/2 = 92 - 3
x/2 = 89
x = 89 * 2
= 178 dollars
So the gas bill of Paul in February is $178. I hope this is the answer you were looking for.
