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2 years ago

3 to the 3rd power times 3 to the second power times 3 to the first Power times 3 to the 0 power times 3 to the negative 1 power

times 3 to the negative 2 power

Mathematics

1 answer:

neonofarm [45]2 years ago

4 0

$3^3\cdot3^2\cdot3^1\cdot3^0\cdot3^{-1}\cdot3^{-2}=3^{3+2+1+0+(-1)+(-2)}=3^3=27\\\\Used:a^n\cdot a^m=a^{n+m}$

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Solve for www. Give an exact answer in simplified form. 53w+13 < 56w + 16

ki77a [65]

The solution will be: $w>-1$

Explanation

The given inequality is: $53w+13 < 56w + 16$

First we will subtract $56w$ from both sides. So.....

$53w+13-56w$

Now we will subtract 13 from both sides. So.....

$-3w$

Then we need to divide both sides by -3. As here we are dividing the inequality by a negative number, so we need to switch the inequality symbol. So, we will get.......

$\frac{-3w}{-3}>\frac{3}{-3}\\ \\ w>-1$

Thus, the solution will be: $w>-1$

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2 years ago

What is 0.8%of $5,700?

EastWind [94]

Answer: 0.8% of 5,700 = 45.6

Step-by-step explanation:

0.8% × 5,700 =

(0.8 ÷ 100) × 5,700 =

(0.8 × 5,700) ÷ 100 =

4,560 ÷ 100 =

45.6;

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3 years ago

Read 2 more answers

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Vesnalui [34]

Michael took the return trip at a velocity 33.75 miles per hour.

<h3>How fast did Michael drive in his return trip?</h3>

Let suppose that Michael drove in straight line road and at constant velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.

First trip

45 = s / 3 (1)

Second trip

v = s / 4 (2)

By (1) and (2):

45 · 3 = 4 · v

v = 33.75 mi / h

Michael took the return trip at a velocity 33.75 miles per hour.

To learn more on velocities: brainly.com/question/18084516

#SPJ1

3 0

1 year ago