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sattari [20]
2 years ago
11

What is the measurement of angel c

Mathematics
2 answers:
horrorfan [7]2 years ago
7 0

Answer:

The measurement of angel c is B.

Murrr4er [49]2 years ago
6 0
It's a vertical angle, which means its equal with angle H
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Alexandra buys sweatshirts for $12 each. In her store, she sells each sweatshirt for $30.
serious [3.7K]
Multiply $30 by .25 you get, it's $7.50so you subtract $7.50 from $30 and you get $22.50. Then multiply 2 (sweaters) by $22.50 and you get $45,but wait you still have to multiply that sales tax so you multiply .04 by $45 and you get $1.80, later you subtract $1.80 from $45 and you get $43.20(the cost of the two sweaters) I did part1 only cuz' no I have no time left Sorry for the inconvenience
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3 years ago
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1 torr is equal to (1 Point)​
shutvik [7]

Answer:

1 torr is equal to 133.322368 pascals

8 0
3 years ago
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15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.
Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = 30C5 = \frac{30 !}{(30-5)!5!} \\

30C5 = 142506 ways

Number of ways of selecting 5 good bulbs  from 26 bulbs = 26C5 = \frac{26 !}{(26-5)!5!} \\

26C5 = 65780 ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = \frac{26C4  * 4C1}{30C5}

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) =  \frac{26C3  * 4C2}{30C5}

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) +  Pr(2 defective) +  Pr(3 defective) +  Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) =  \frac{26C2  * 4C3}{30C5}

Pr(3 defective) = 0.009

Pr(4 defective) =  \frac{26C1  * 4C4}{30C5}

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0
3 years ago
What are the ordered pairs of the
OlgaM077 [116]

Answer:

The two points solutions to the system of equations are: (2, 3) and (-1,6)

Step-by-step explanation:

These system of equations consists of a parabola and a line. We need to find the points at which they intersect:

x^2-2x+3=-x+5\\x^2-2x+x+3-5=0\\x^2-x-2=0\\(x-2)(x+1)=0

Since we were able to factor out the quadratic expression, we can say that the x-values solution of the system are:

x = 2 and x = -1

Now, the associated y values we can get using either of the original equations for the system. We pick to use the linear equation for example:

when x = 2 then  y=-(2)+5=3

when x= -1  then  y=-(-1)+5=6

Then the two points solutions to the system of equations are: (2, 3) and (-1,6)

6 0
3 years ago
How do you solve for y in the equation: <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D%20%3Dy-6" id="TexFormula1" title
kozerog [31]

No it isn't.

Explanation:

x/y * y = (y-6) * y

x = y^2 - 6y

A function gives just one y for every x

In this case there will always be 2 y's for every x

Example:

y can be

y = 6

or

y =−6

(0,-6) & (0,6)

5 0
3 years ago
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