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WARRIOR [948]
2 years ago
14

The table below shows the distribution of students by age in a high school

Mathematics
2 answers:
snow_lady [41]2 years ago
8 0

Answer is 28

Hope This helps

Firlakuza [10]2 years ago
8 0

Answer:

0.25

Step-by-step explanation:

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5-{3+2[5-4(64÷8)]-12}
anygoal [31]
The answer that I got was 29
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3 years ago
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Could someone please explain how to solve for the area?
mixas84 [53]

9514 1404 393

Answer:

  779.4 square units

Step-by-step explanation:

You seem to have several problems of this type, so we'll derive a formula for the area of an n-gon of radius r.

One central triangle will have a central angle of α = 360°/n. For example, a hexagon has a central angle of α = 360°/6 = 60°. The area of that central triangle is given by the formula ...

  A = (1/2)r²sin(α)

Since there are n such triangles, the area of the n-gon is ...

  A = (n/2)r²sin(360°/n)

__

For a hexagon (n=6) with radius 10√3, the area is ...

  A = (6/2)(10√3)²sin(360°/6) = 450√3 ≈ 779.4 . . . . square units

8 0
2 years ago
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If an image of a triangle is congruent to the pre image then the scale factor of the dilation must be n=
Kazeer [188]
1. the image is multiplied by the scale factor. if the scale factor is 2, the image is twice the size of the preimage. if the scale factor is ⅓, the image is one third the size. only a scale factor of 1 preserves congruency
5 0
3 years ago
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For the function, f(x)=(9x+7)/(2x+4)
AVprozaik [17]
A. f(x)=\frac{9x+7}{2x+4}\\f'(x)=\frac{(9)(2x+4)-(9x+7)(2)}{(2x+4)^2}\\f'(x)=\frac{(18x+36)-(18x+14)}{(2x+4)(2x+4)}\\f'(x)=\frac{22}{4x^2+16x+16}\\f'(x)=\frac{11}{2x^2+8x+8}\\\frac{11}{(2x+4)(x+2)}=0\\\frac{1}{(2x+4)(x+2)}=0\\x=-\infty,\infty - There are no critical points because the graph is neither continuous nor smooth. There is a discontinuity at x = 2.

B. \frac{1}{(2x+4)(x+2)}=0\\x=-\infty,\infty - The absolute maximum is f(lim⇒-2_-) = infinity. The absolute minimum is f(lim⇒-2_+) = -infinity. This applies to the interval [-10, 7].

C. f(x)=\frac{9x+7}{2x+4}\\f(0)=\frac{9(0)+7}{2(0)+4}\\f(0)=\frac{7}{4}\\f(0)=1.75\\f(5)=\frac{9(5)+7}{2(5)+4}\\f(5)=\frac{45+7}{10+4}\\f(5)=\frac{52}{14}\\f(5)=\frac{26}{7}\\f(5)=3.714 - The absolute maximum is f(5) = 26/7 or 3.714. The absolute mimimum is f(0) = 1.75. This applies to the interval [0, 5]. Proof: graph f(x) at [0, 5] on a graph or graphing calculator.
5 0
3 years ago
What is the measure of angle B in the figure below?<br> о 30°<br> О 45°<br> О 60°<br> O90°
Slav-nsk [51]

Answer:

45°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cosB = \frac{adjacent}{hypotenuse} = \frac{3}{3\sqrt{2} } = \frac{1}{\sqrt{2} }, hence

B = cos^{-1}( \frac{1}{\sqrt{2} } ) = 45°

6 0
3 years ago
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