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2 years ago

13

Help ASAP PLEASE!!!!!

1 answer:

Naily [24]2 years ago

3 0

Answer:

Its A

PLS MARK AS BRAINLESS I MEAN BRAINLIEST

Step-by-step explanation:

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Is Point M the midpoint of AB? Select Yes or No for each statement.

nexus9112 [7]

Answer:

A is No.

B is Yes.

C is Yes.

D is No.

5 0

4 years ago

Read 2 more answers

2 3/8 - 4 1/2 + 3 1/8 - (1/2)

UkoKoshka [18]

let's convert the mixed fractions to improper fractions firstly.

$\bf \stackrel{mixed}{2\frac{3}{8}}\implies \cfrac{2\cdot 8+3}{8}\implies \stackrel{improper}{\cfrac{19}{8}}~\hfill \stackrel{mixed}{4\frac{1}{2}}\implies \cfrac{4\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{9}{2}} \\\\\\ \stackrel{mixed}{3\frac{1}{8}}\implies \cfrac{3\cdot 8+1}{8}\implies \stackrel{improper}{\cfrac{25}{8}} \\\\[-0.35em] ~\dotfill$

$\bf \cfrac{19}{8}-\cfrac{9}{2}+\cfrac{25}{8}-\cfrac{1}{2}\implies \stackrel{\textit{using an LCD of 8}}{\cfrac{(1)19-(4)9+(1)25-(4)1}{8}}\implies \cfrac{19-36+25-4}{8} \\\\\\ \cfrac{4}{8}\implies \cfrac{1}{2}$

8 0

3 years ago

2 7/10 as a decimal please again I’m sorry

const2013 [10]

2.7 would be 2 7/10. Correct?

7 0

3 years ago

Read 2 more answers

hhhhhhhhhhhhhhhhuuuuuuuuuuuuuuuurrrrrrrrrrrrrrrrrryyyyyyyyyyyyyyyyyyyyyyy ppppppppppppppllllllllllllllllllllllllllllllllllllllll

zavuch27 [327]

Answer:

A. 3 1/4

Step-by-step explanation:

Convert the mixed numbers to improper fractions, then find the LCD and combine.

8 0

3 years ago

Read 2 more answers

What are the coordinates of the center and the

Misha Larkins [42]

Answer: The coordinate of the center is (4,-3)

radius = 8

Step-by-step explanation:

Given ;

$x^{2} +y^{2}=8x-6y+39$

re - arranging , we have

$x^{2} +y^{2}-8x+6y-39=0$

comparing with the general equation

$x^{2} +y^{2}+2gx+2fy+c=0$

This means that

$2gx = -8x$

$2g=-8$

$g=-4$

also

$2fy=6y$

$2f=6$

$f=3$

$c=-39$

The coordinate of the center is (-g,-f)

Therefore;

the coordinate of the center = (4,-3)

the formula for calculating r is given by:

$r = \sqrt{g^{2}+f^{2}-c}$

$r = \sqrt{16+9+39}$

$r=\sqrt{64}$

$r=8$

METHOD 2

$x^{2} +y^{2}-8x+6y-39=0$

using completing the square method , we have

$x^{2} -8x+y^{2}+6y-39=0$

completing the square , we have

$(x-4)^{2}+(y+3)^{2} = 39 +4^{2}+3^{2}$

$(x-4)^{2}+(y+3)^{2}=64$

comparing with the general equation

$(x-a)^{2}+(y-b)^{2}=r^{2}$

where a and b are the coordinate of the center , that is

the coordinate of the center is ( 4 , -3)

$r^{2}=64$

$r=8$

6 0

3 years ago