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3 years ago

13

hhhhhhhhhhhhhhhhuuuuuuuuuuuuuuuurrrrrrrrrrrrrrrrrryyyyyyyyyyyyyyyyyyyyyyy ppppppppppppppllllllllllllllllllllllllllllllllllllllll

llllllllllllllllllllllllllzzzzzzzzzzzzzzzzzzzzzzzzz

2 answers:

zavuch27 [327]3 years ago

8 0

Answer:

A. 3 1/4

Step-by-step explanation:

Convert the mixed numbers to improper fractions, then find the LCD and combine.

docker41 [41]3 years ago

3 0

Hi there!

it would be...3 1/4

<em><u>1.Convert into same denominator:</u></em>

<em><u /></em> $11\frac{3}{4}=11\frac{3}{4}$ <em><u /></em>

<em><u /></em> $8\frac{1}{2}=8\frac{2}{4}$ <em><u /></em>

<em><u>2.Subtract the two fraction terms:</u></em>

<em><u /></em> $11\frac{3}{4}-8\frac{2}{4}=3\frac{1}{4}$ <em><u /></em>

Therefore, it would be 3 1/4.

<em><u /></em>

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Lines a and b are parallel. line c is perpendicular to both line a and line B. Which statement about lines a,b and C is not true

7nadin3 [17]

When lines are parallel, they have the same slope, so the statement "line a and line b have the same slope" is TRUE

When lines are perpendicular, the slopes are opposites (the sign and number is flipped)

For example:

slope is 2

perpendicular line's slope is -1/2

slope is -1

perpendicular line's slope is 1/1 or 1

slope is 4/5

perpendicular line's slope is -5/4

When you multiply(the product) perpendicular slopes together, they equal -1. Since line c is perpendicular to line a and line b, the product of their slopes is -1.(so this is true)

The statement "the sum of the slopes of line a and b is 0" is false because if they have the same slope, when added together the result would not be 0. The slopes of line a and line b is -2/3, so the sum would be -4/3.

7 0

3 years ago

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Thank you!!! 20 points

GREYUIT [131]

Answer:

Assuming that the figure is a rectangle:

x=12

angle GJH=22 degrees

Step-by-step explanation:

angle GHJ=angle IJH

5x+8=7x-16

simplify

2x=24

x=12

angle IJH=7x-16

substituting for x

IJH=7(12)-16=84-16=68 degrees

angle GJH=90-IJH

angle GJH=22 degrees

5 0

3 years ago

What is the Factors of 6

Goryan [66]

Answer:

1, 2, 3, 6

Step-by-step explanation:

Factors are numbers that divide evenly into another number.

6 0

2 years ago

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What is the value of cosθ given that (−2, −3) is a point on the terminal side of θ ?

snow_tiger [21]

Answer:

-0.555

Step-by-step explanation:

The terminal point of the vector in this problem is

(-2,-3)

So, it is in the 3rd quadrant.

We want to find the angle $\theta$ that gives the direction of this vector.

We can write the components of the vector along the x- and y- direction as:

$v_x = -2\\v_y = -3$

The tangent of the angle will be equal to the ratio between the y-component and the x-component, so:

$tan \theta = \frac{v_y}{v_x}=\frac{-3}{-2}=1.5\\\theta=tan^{-1}(1.5)=56.3^{\circ}$

However, since we are in the 3rd quadrant, the actual angle is:

$\theta=180^{\circ} + 56.3^{\circ} = 236.3^{\circ}$

So now we can find the cosine of the angle, which will be negative:

$cos \theta = cos(236.3^{\circ})=-0.555$

7 0

3 years ago

Which correctly describes how the graph of the inequality 6y − 3x > 9 is shaded? -Above the solid line

baherus [9]

The statement which correctly describes the shaded region for the inequality is $\fbox{\begin\\\ Above the dashed line\\\end{minispace}}$

Further explanation:

In the question it is given that the inequality is $6y-3x>9$ .

The equation corresponding to the inequality $6y-3x>9$ is $6y-3x=9$ .

The equation $6y-3x=9$ represents a line and the inequality $6y-3x>9$ represents the region which lies either above or below the line $6y-3x=9$ .

Transform the equation $6y-3x=9$ in its slope intercept form as $y=mx+c$ , where $m$ represents the slope of the line and $c$ represents the $y$ -intercept.

$y$ -intercept is the point at which the line intersects the $y$ -axis.

In order to convert the equation $6y-3x=9$ in its slope intercept form add $3x$ to equation $6y-3x=9$ .

$6y-3x+3x=9+3x$

$6y=9+3x$

Now, divide the above equation by $6$ .

$\fbox{\begin\\\math{y=\dfrac{x}{2}+\dfrac{1}{2}}\\\end{minispace}}$

Compare the above final equation with the general form of the slope intercept form $\fbox{\begin\\\math{y=mx+c}\\\end{minispace}}$ .

It is observed that the value of $m$ is $\dfrac{1}{2}$ and the value of $c$ is $\dfrac{3}{2}$ .

This implies that the $y$ -intercept of the line is $\dfrac{3}{2}$ so, it can be said that the line passes through the point $\fbox{\begin\\\ \left(0,\dfrac{3}{2}\right)\\\end{minispace}}$ .

To draw a line we require at least two points through which the line passes so, in order to obtain the other point substitute $0$ for $y$ in $6y=9+3x$ .

$0=9+3x$

$3x=-9$

$\fbox{\begin\\\math{x=-3}\\\end{minispace}}$

This implies that the line passes through the point $\fbox{\begin\\\ (-3,0)\\\end{minispace}}$ .

Now plot the points $(-3,0)$ and $\left(0,\dfrac{3}{2}\right)$ in the Cartesian plane and join the points to obtain the graph of the line $6y-3x=9$ .

Figure $1$ shows the graph of the equation $6y-3x=9$ .

Now to obtain the region of the inequality $6y-3x>9$ consider any point which lies below the line $6y-3x=9$ .

Consider $(0,0)$ to check if it satisfies the inequality $6y-3x>9$ .

Substitute $x=0$ and $y=0$ in $6y-3x>9$ .

$(6\times0)-(3\times0)>9$

$0>9$

The above result obtain is not true as $0$ is not greater than $9$ so, the point $(0,0)$ does not satisfies the inequality $6y-3x>9$ .

Now consider $(-2,2)$ to check if it satisfies the inequality $6y-3x>9$ .

Substitute $x=-2$ and $y=2$ in the inequality $6y-3x>9$ .

$(6\times2)-(3\times(-2))>9$

$12+6>9$

$18>9$

The result obtain is true as $18$ is greater than $9$ so, the point $(-2,2)$ satisfies the inequality $6y-3x>9$ .

The point $(-2,2)$ lies above the line so, the region for the inequality $6y-3x>9$ is the region above the line $6y-3x=9$ .

The region the for the inequality $6y-3x>9$ does not include the points on the line $6y-3x=9$ because in the given inequality the inequality sign used is $>$ .

Figure $2$ shows the region for the inequality $\fbox{\begin\\\math{6y-3x>9}\\\end{minispace}}$ .

Therefore, the statement which correctly describes the shaded region for the inequality is $\fbox{\begin\\\ Above the dashed line\\\end{minispace}}$

Learn more:

A problem to determine the range of a function brainly.com/question/3852778
A problem to determine the vertex of a curve brainly.com/question/1286775
A problem to convert degree into radians brainly.com/question/3161884

Answer details:

Grade: High school

Subject: Mathematics

Chapter: Linear inequality

Keywords: Linear, equality, inequality, linear inequality, region, shaded region, common region, above the dashed line, graph, graph of inequality, slope, intercepts, y-intercept, 6y-3x=9, 6y-3x>9, slope intercept form.

4 0

3 years ago

Read 2 more answers