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Lyrx [107]
3 years ago
13

Distance between the points (0,-3) and (-8,1).

Mathematics
1 answer:
QveST [7]3 years ago
4 0

[Hello,BrainlyUser]

Answer:

 \sqrt[4]{5}  

Step-by-step explanation:

Use the distance formula to determine the distance between the two points.

Formula :  \sqrt{(x_2-x_1)^2+(y_2-y_1)^2

Substitute the actual values of the points into the distance formula.

\sqrt{(-8-0)^2 +(1-(-3)^2}

[CloudBreeze]

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Step-by-step explanation:

Line AB = sqrt18 = 4.24

Line BC = sqrt10 = 3.16

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Since the triangle cannot be isosceles or equilateral, the best option here is scalene.

4 0
3 years ago
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A fast food restaurant sells between 164 and 328 hamburgers per day. If the company profits $82.00 per 82 hamburgers sold, appro
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The graph of an equation is shown below:
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6 0
4 years ago
Two trains leave towns 1490 kilometers apart at the same time and travel toward each other. One train travels 20 km/h slower tha
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Answer:

the rate of each train is 139 km/h and 159 km/h.

Step-by-step explanation:

let

v = the rate of the slower train

v + 20 = the rate of the faster train

d = 1490 km the distance that the two train will travel

t = 5 hr the time of the travel

since speed = distance/time => distance = speed*time

v*t + (v+20)t = d

5v + 5(v + 20) = 1490

5v+5(v+20)=1490

Step 1: Simplify both sides of the equation.

5v+5(v+20)=1490

5v+(5)(v)+(5)(20)=1490(Distribute)

5v+5v+100=1490

(5v+5v)+(100)=1490(Combine Like Terms)

10v+100=1490

10v+100=1490

Step 2: Subtract 100 from both sides.

10v+100−100=1490−100

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Step 3: Divide both sides by 10.

10v/10 = 1390/10

v = 139km/h

Next

we add 139 to 20

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the rate of each train is 139 km/h and 159 km/h.

7 0
3 years ago
Help me please idk how to do this
marissa [1.9K]
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N_{butterscotch}=4


7 0
3 years ago
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