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Genrish500 [490]
3 years ago
8

The formula for the volume of a cylinder with a height of 5 units is v(r)=5(3.14)r^2 where r is the radius of the cylinder. What

is the domain and range of the cylinder?
Mathematics
1 answer:
LekaFEV [45]3 years ago
4 0

Answer:

r>0 and V(r)>0

Step-by-step explanation:

Number one: There arent no negative volumes

Number two: There aren't Negative radi

Thus V(r) and r must be more noteworthy than one.

I connect the chart V(r)=5 Pi r^2

The space would be (0,infinity)

The run would be (0, infinity)

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Polygon WXYZ has vertices W(−2,−1) , X(−2,3) , Y(0,4) , and Z(0,0) . After a dilation the vertices of the image are W'(−4,−2) ,
Fiesta28 [93]

Answer:

scale factor (k) is 2

Step-by-step explanation:

Look at W and W'. W is (-2, -1), but W' says (-4, -2). 2 x 2 is 4 and 1 x 2 is 2. Both coordinates were multiplied by 2. The same goes for all the other vertices, so it would be k = 2.

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2 years ago
Question 2 (2 points)
hoa [83]

Answer:

4) The limit does not exist.

General Formulas and Concepts:

<u>Calculus</u>

Limits

  • Right-Side Limit:                                                                                             \displaystyle \lim_{x \to c^+} f(x)
  • Left-Side Limit:                                                                                               \displaystyle \lim_{x \to c^-} f(x)

Limit Rule [Variable Direct Substitution]:                                                             \displaystyle \lim_{x \to c} x = c

Step-by-step explanation:

*Note:

For a limit to exist, the right-side and left-side limits must be equal to each other.

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x ,\ x < 5\\8 ,\ x = 5\\x + 3 ,\ x > 5\end{array}

<u>Step 2: Find Left-Side Limit</u>

  1. Substitute in function [Left-Side Limit]:                                                       \displaystyle \lim_{x \to 5^-} 5 - x
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                          \displaystyle \lim_{x \to 5^-} 5 - x = 5- 5 = 0

<u>Step 2: Find Left-Side Limit</u>

  1. Substitute in function [Right-Side Limit]:                                                     \displaystyle \lim_{x \to 5^+} x + 3
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle \lim_{x \to 5^+} x + 3 = 5 + 3 = 8

∴ since  \displaystyle \lim_{x \to c^+} f(x) \neq \lim_{x \to c^-} f(x)  ,  \displaystyle  \lim_{x \to 5} f(x) = \text{DNE}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

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12x42=504

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For a week= 504x7

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