<em>The word usage in last sentence of the question is not well presented. However, I can understand that you intend to solve for the width of the park</em>
Answer:
Step-by-step explanation:
Given
Required
Determine the Width
For a rectangle:
Substitute for Area and Length
Multiply both sides by 
You are not asking any question. Maybe you want the way how to write it. If so:
2^5/(-3)=2^5/(-3)=2^5/(-3)
There are 45 girls in Jonathan's class.
Sec(theta) = 1 / cos (theta) = hypotenuse / x -coordinate
hypotenuse = 1 (because it is the radius of the unit circle)
sec (theta) = 1 / (-3/5) = - 5/3
cot (theta) = 1 / tan(theta) = x-coordinate / y - coordinate
cot (theta) = -3/5 / y
y^2 + (-3/5)^2 = 1 => y^2 = 1 - 9/25 = 16/25 = y = +/- 4/5
Third quadrant => y = -4/5
=> cot (theta) = (-3/5) / (-4/5) = 3/4
