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ArbitrLikvidat [17]
2 years ago
5

3⋅f(−4)−3⋅g(−2)= i dont know how to solve this

Mathematics
1 answer:
Slav-nsk [51]2 years ago
7 0

Answer:The value of the given function is 6

Step-by-step explanation:

Given the following expression 3*f(-4)-3*g(-2), to find the values, we can assume that;

f(-4) = 10g(-2) = 8

Substitute the given parameters into the expression to have:

3*f(-4)-3*g(-2)

= 3((10) - 3(8)

= 30 - 24

= 6

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Step-by-step explanation:

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Determine all numbers at which the function is continuous. <br> Picture provided below
Ne4ueva [31]

Answer:

Choice D

Step-by-step explanation:

The function will be continuous everywhere except where the function in the denominator is 0. We, therefore determine the value(s) of x for which the function will be 0;

x^{2} -6x+8=0\\x^{2} -2x-4x+8=0\\x(x-2)-4(x-2)=0\\(x-4)(x-2)=0\\x=4\\x=2

Therefore, the points x= 2 and x =4 are points of discontinuity

5 0
4 years ago
Round 117.22666 to the nearest tenths
zzz [600]

Answer:

117.2

Step-by-step explanation:

Rounding a number to the nearest tenth:

A number rounded to the nearest tenth will have one decimal place.

To do this, we look at the second decimal digit.

If it is less than 5, the first decimal digit is kept.

Otherwise, one is added to the first decimal digit.

In this question:

117.22666

The second decimal digit is 2, which means that we keep the first decimal digit which is also 2.

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6 0
3 years ago
Degree 3 polynomial with zeros -7, 3i, and -3i
d1i1m1o1n [39]

A polynomial having degree 3 with zeros -7, 3i, and -3i is:
x³+ 7x² - 9x - 63

The correct answer is an option (A)

In this question, we need to find the polynomial whose degree is 3 polynomial and zeros are -7, 3i, and -3i

The zeros of the required polynomial = -7, 3i, and -3i

This means, the roots of the polynomial = (x + 7), (x - 3i) and (x + 3i)

We know that in complex numbers, i = √-1

So, 3i = 3√-1

          = √-9

i.e., the roots of the polynomial are (x + 7), (x - √-9) and (x + √-9)

And the polynomial would be,

(x + 7)(x - √-9)(x + √-9)

= (x + 7)(x² - (√-9)²)

= (x + 7)(x² - (-9))

= (x + 7)(x² + 9)

=  x³+ 7x² - 9x - 63

Therefore, a polynomial having degree 3 with zeros -7, 3i, and -3i is:
x³+ 7x² - 9x - 63

The correct answer is an option (A)

Learn more about the polynomial here:

brainly.com/question/14344049

#SPJ1

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Y = 2x - 1<br> y = x-4<br><br> Graph equation
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this is simply ok with help

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