I need to solve the equation for z

Mathematics

2 answers:

Greeley [361]4 years ago

7 0

I think this is how you do it...

babunello [35]4 years ago

4 0

to the risk of sounding redundant.

well, let's bear in mind that the LCD for all three fractions will just be "xyz", so then let's multiply both sides by that LCD in order to do away with the denominators and then solve for "z".

$\bf \cfrac{2}{x}=\cfrac{3}{y}+\cfrac{1}{z}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{xyz}}{xyz\left( \cfrac{2}{x} \right)=xyz\left( \cfrac{3}{y}+\cfrac{1}{z} \right)}\implies 2yz=3xz+xy \\\\\\ 2yz-3xz=xy\implies \stackrel{\textit{common factor}}{z(2y-3x)}=xy\implies z=\cfrac{xy}{2y-3x}$

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The 95% confidence interval for the true proportion would be given by (0.570;0.630) .

And if we convert this into % we got (57.0%, 63.0%)

Step-by-step explanation:

The information given we have the following info given:

$n = 1019$ represent the sampel size

$\hat p=0.6$ represent the sample proportion of interest

The confidence level is 95%, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: