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Bezzdna [24]
3 years ago
7

I need to solve the equation for z

Mathematics
2 answers:
Greeley [361]3 years ago
7 0
I think this is how you do it...

babunello [35]3 years ago
4 0

to the risk of sounding redundant.

well, let's bear in mind that the LCD for all three fractions will just be "xyz", so then let's multiply both sides by that LCD in order to do away with the denominators and then solve for "z".

\bf \cfrac{2}{x}=\cfrac{3}{y}+\cfrac{1}{z}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{xyz}}{xyz\left( \cfrac{2}{x} \right)=xyz\left( \cfrac{3}{y}+\cfrac{1}{z} \right)}\implies 2yz=3xz+xy \\\\\\ 2yz-3xz=xy\implies \stackrel{\textit{common factor}}{z(2y-3x)}=xy\implies z=\cfrac{xy}{2y-3x}

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The equations of the perpendicular lines are: y = 1/2x + 6, y = 15, y = -x - 2, y = 6x + 3 and y = 1/3x - 4

<h3>How to determine the equations?</h3>

When a linear equation is represented as:

Ax + By = C

The slope (m) is:

m = -A/B

When the linear equation is represented as:

y = mx + c

The slope is m

A line perpendicular to a linear equation that has a slope of m would have a slope of -1/m

Using the above highlights, the equations of the lines are:

<u>6. y = -2x + 5; (2, 7)</u>

The slope is:

m = -2

The perpendicular slope is:

n = 1/2

The equation of the perpendicular line is:

y = n(x - x1) + y1

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y = 1/2(x - 2) + 7

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y = 1/2x - 1 + 7

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y = 1/2x + 6

<u>7. y = -5; (11, 15)</u>

The slope is:

m = 0

The perpendicular slope is:

n = 1/0 = undefined

The equation of the perpendicular line is:

y = n(x - x1) + y1

This gives

y = 15

<u>8. Graph ; (-12, 10)</u>

The slope is:

m = (y2 - y1)/(x2 - x1)

Using the points on the graph, we have:

m = (2 - 3)/(3 - 4)

m = 1

The perpendicular slope is:

n = -1

The equation of the perpendicular line is:

y = n(x - x1) + y1

This gives

y = -1(x + 12) + 10

y = -x - 12 + 10

Evaluate

y = -x - 2

<u>9. y = -1/6x + 1; (-2, -9)</u>

The slope is:

m = -1/6

The perpendicular slope is:

n = 6

The equation of the perpendicular line is:

y = n(x - x1) + y1

This gives

y = 6(x + 2) - 9

Evaluate

y = 6x + 12 - 9

This gives

y = 6x + 3

<u>10. 6x + 2y = 14; (12, 0)</u>

The slope is:

m = -6/2

m = -3

The perpendicular slope is:

n = 1/3

The equation of the perpendicular line is:

y = n(x - x1) + y1

This gives

y = 1/3(x - 12) + 0

Evaluate

y = 1/3x - 4

Hence, the equations of the perpendicular lines are: y = 1/2x + 6, y = 15, y = -x - 2, y = 6x + 3 and y = 1/3x - 4

Read more about linear equations at:

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