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2 years ago

Pls help dum answer=report question in picture

Mathematics

1 answer:

prisoha [69]2 years ago

6 0

Answer:

The third one because its the only one that doesn't have the same (x) twice

Step-by-step explanation:

lmk if this helped

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Use long division to find the quotient Q(x) and the remainder R(x) when P(x) is divided by d(x) and express P(x) in the for

lilavasa [31]

Answer:

$P(x)=(x+9)(x^2-7x+52)+3$

Step-by-step explanation:

We are given that

$P(x)=x^3+2x^2-11x+471$

$d(x)=x+9$

We have to find the value of Q(x) and Remainder R(x).

Quotient, $Q(x)=x^2-7x+52$

Remainder, $R(x)=3$

We know that

$Dividend=Divisor\times Quotient+Remainder$

$P(x)=(x+9)(x^2-7x+52)+3$

4 0

3 years ago

My calculator wasn’t working for this I’m not sure how to solve it but help would be coolio

ziro4ka [17]

We know that:

$_nP_k = \dfrac{n!}{(n-k)!}$

so in this case $n = 5$ , $k=3$ and:

$_5P_3=\dfrac{5!}{(5-3)!}=\dfrac{5!}{2!}=\dfrac{5\cdot4\cdot3\cdot2\cdot1}{2\cdot1}=\dfrac{120}{2}=\boxed{60}$

4 0

3 years ago

A semicircle has the radius of 2 4/5. What is its area? leave your answers in term of π

Ratling [72]

Answer:

$11\dfrac{13}{25}\pi$

Step-by-step explanation:

r = Radius of semicircle = $2\dfrac{4}{5}=\dfrac{24}{5}\ \text{units}$

Area of semicircle is given by

$A=\dfrac{\pi r^2}{2}\\\Rightarrow A=\dfrac{\pi \left(\dfrac{24}{5}\right)^2}{2}\\\Rightarrow A=\dfrac{288}{25}\pi=11\dfrac{13}{25}\pi\ \text{sq. units}$

The area of the semicircle is $11\dfrac{13}{25}\pi\ \text{sq. units}$ .

4 0

3 years ago

I need help with triangulation

slavikrds [6]

More details are needed

7 0

3 years ago

Heidi hikes two trails, the Big Trapezoid and the Little Trapezoid. The shorter base of the Big Trapezoid is 2 mi long, while th

Bas_tet [7]

Two trapezoid are similar
so it has some scale factor
look longer base of a big trap is 8 mi,and longer base of shorter trap is 4mi.
so that is half of big trapezoid.
so little trapezoid base should be 1 as big trap's shorter base is 2mi<span />

3 0

3 years ago