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lukranit [14]
3 years ago
6

Solve (x^2+4)(x^2-4)

Mathematics
2 answers:
timurjin [86]3 years ago
3 0
<span>(x^2+4)(x-2)(x+2)orx^4 - 16</span>
wolverine [178]3 years ago
3 0
If you need to expand, you multiply all the terms:

x^2 * x^2 = x^4
x^2 * -4 = -4x^2
4 * x^2 = 4x^2
4 * -4 = -16

And then combine:

x^4 - 4x^2 + 4x^2 - 16

Which becomes:

x^2 - 16
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A dog weighs two pounds less than three times the weight of a cat. The dog also weights twenty-two more pounds than the cat. Wri
Solnce55 [7]

Answer:

the cat weighs 21 pounds.

the dog weighs 43 pounds

Step-by-step explanation:

dog = 3x-20 = x + 22

cat = x

3x-20 = x+22

3x = x+42 (add 20 to both sides)

2x = 42 (subtract x from both sides)

x = 21

4 0
3 years ago
I need help Please help.
asambeis [7]

Answer:

Step-by-step explanation:

Number of students 10

Problem 1. $625 for the bus hire per friday, So 625*4=$2500

Problem 2. 2500/25=$100 each for the whole 4 weeks

Problem 3.

10 students tickets 220= 2200 for all tickets. The bus, 625/10 = $62.5*4= $250 dollars for the whole 4 weeks for the bus so in all each student pays $470 each

20 students, tickets 220=4400 for all tickets. The bus, 625/20=$31.25*4=$125 for the whole 4 weeks for the bus, so in all each student must pay $345 each

30 students, tickets 220 = 6600 for all tickets. The bus, 625/30 =$20.83*4=$83.32 for the whole 4 weeks for the bus, so in all each student must pay $303.32 each

41 students, tickets $160=$6560 for all tickets. The bus, because you need 2 buses at 625 each so $1250 for both buses 1250/41= 30.49*4=$121.96 for the whole 4 weeks for the bus. So in al each student must pay $281.96 each

Hope this is correct

8 0
3 years ago
Sum1 plssss help me!! i'll give brainliest!
Serga [27]
The range of the function is C.

When a questions asks about the RANGE of the function, they are specifically talking about Y-VALUES. If a questions asks about DOMAIN, they want the X-VALUES.

This is a quadratic function.

A and B could be eliminated right away since range asks for y-values, not x-values.
4 0
3 years ago
Read 2 more answers
Do you agree with the statement that " cubic functions must have at least 1 x-intercept but not more than 3, whereas quadratic f
vladimir2022 [97]

Answer:

Yes, I agree

Step-by-step explanation:

For the cubic function

A cubic function is represented as:

f(x)=ax^3+bx^2+cx+d

A cubic function may have 1, 2 or 3 x intercepts. This is shown below

For 3 x intercepts

y = x^3 - x

Equate y to 0

x^3 - x = 0

Expand

x(x^2 - 1) = 0

Express x^2 - 1 as difference of two squares

x(x - 1)(x +1 ) = 0

<em>x = 0 or 1 or -1</em>

For 2 x intercepts

y = x^3 - x

y  =(x-5)^2)(x+7)

Equate y to 0

(x-5)^2(x+7) = 0

Expand

(x-5)(x-5)(x+7) = 0

<em>x= 5 or x = -7</em>

For 1 x intercept

y = x^3

Equate y to 0

x^3 = 0

Take cube roots of both sides

x = 0

It has been shown above that a cubic function may have 1, 2 or 3.

So, I agree to the statement

For the quadratic function

A quadratic function will not have any x intercept when the function can not be factorized;

E.g.

y = x^2 + x + 17

<em>The above function has no x intercept.</em>

A quadratic function will have at least 1 x intercept when the function can be factorized;

E.g.

y = x^2- 6x + 9

Equate y to 0

x^2- 6x + 9 = 0

Expand

x^2 - 3x - 3x + 9 = 0

(x - 3)(x-3) = 0

x = 3

We've shown that a quadratic may have no x intercept, and it may also have x intercept(s)

Hence, I agree to both statement

3 0
2 years ago
What is the distance between 15 miles east and 12 miles west?
inysia [295]

Answer:

27 miles.

Step-by-step explanation:

if you count from the 15 miles from the east to the 12 miles in the west, it would add up to 27. hope this helped

7 0
2 years ago
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