Question

I NEED HELP PLSS I CANT GET THIS WRONG

Answer 1

$\frac{(4v^{-3})^3}{3v^{-8}} =\frac{64v^{-9} }{3v^{-8} } =\frac{64}{3} v^{-9--8} =\frac{64}{3} v^{-1} = \frac{64}{3v}$

Hope that helps!

Answer 2

In simplest form is 64/3v hope it helps!