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dybincka [34]
2 years ago
6

A population of 30 swans halves every 10yr. Which graph represents the population growth?

Mathematics
2 answers:
Anton [14]2 years ago
8 0

Answer:

The second graph

Step-by-step explanation:

If the population halves every 10 years, the population at year 10 would be half as mush as year 0, and year 20 would have half as much as year 20, and so on, graph 2 is the only one with a decreasing slope.

lianna [129]2 years ago
3 0

Answer:

B

Step-by-step explanation:

I got it right on my test

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How many triangles???
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Answer:

4

Step-by-step explanation:

The triangle itself

Also the 3 at the top

They are the only ones with 3 sides

6 0
3 years ago
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If f(x) = (2x^3 − 4)^6, then what is f '(x)?
Dominik [7]
The correct answer is:

6(2x^3-4)^5(6x^2)

Explanation:

That is the derivative after you differentiate using the Chain Rule.
4 0
3 years ago
A rectangular park had a perimeter of 18 miles. It is 7 miles wide. What is the area of the park?
4vir4ik [10]
Perimeter = 18 miles
Perimeter = 2a + 2b
2a + 2b = 18

a = ?
b = 7

18 = 2a + 2*7
18 = 2a + 14
2a = 18 - 14
2a = 4
a = 2

Area = a * b
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7 0
3 years ago
It costs $2.55 to make a sandwich at the local deli shop. To make a profit, the deli sells it at a price that is 140% of the cos
gulaghasi [49]
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8 0
3 years ago
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Why is the equation y-y1=m(x-x1) called the point-slope form?
MatroZZZ [7]

Answer:

The equation of the line with slope m = 2 and passing through the point (1, 1) will be:

y = 2x

Step-by-step explanation:

We know that the point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

The formula y-y_1=m\left(x-x_1\right) is termed as the point-slope form of the line equation because if we know one point on a certain line and the slope of that line, then we can easily get the line equation with this formula and, hence, determine all other points on the line.

For example, if we are given the point (1, 1) and slope m = 2

Then substituting the values m = 2 and the point (1, 2)

y-y_1=m\left(x-x_1\right)

y - 2 = 2(x-1)

y - 2 = 2x-2

y = 2x-2+2

y = 2x

Therefore, the equation of the line with slope m = 2 and passing through the point (1, 1) will be:

y = 2x

5 0
2 years ago
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