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Butoxors [25]
2 years ago
7

56, 85, 64, 51, 23, 43, 82, 77, 50 what's the Mean, Median, Mode, Range​

Mathematics
1 answer:
Nezavi [6.7K]2 years ago
5 0

Answer:

Explanation

Step-by-step explanation:

Median is 56.

To calculate median you have to sort the numbers least to greatest and find the middle number sometimes there is 2 when there is an even number for the numbers in the dataset.

Mean 59.

For mean you add up all the scores and then divide them by the number of scores there were but for this case numbers.

56 + 85=141 + 64=205 + 51=256 + 23=279 + 43=322 + 82=404 + 77=481 + 50=531 divided by 9=59

Mode

Is all of them because mode is the number that appears most in the data set and in our data set every number only appears once so all of them>

Range is 62

Because range is highest number subtracting our lowest number so highest number=85

Our lowest number is 23

so 85 - 23=62

Hope this helps have a great day:)

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3 years ago
Which graph represents the function f (x) = StartFraction 2 Over x minus 1 EndFraction + 4?
Pepsi [2]

Answer:

On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4

Step-by-step explanation:

The given function is presented as follows;

f(x) = \dfrac{2}{x - 1} + 4

From the given function, we have;

When x = 1, the denominator of the fraction, \dfrac{2}{x - 1}, which is (x - 1) = 0, and the function becomes, \dfrac{2}{1 - 1} + 4 = \dfrac{2}{0} + 4 = \infty + 4 = \infty therefore, the function in undefined at x = 1, and the line x = 1 is a vertical asymptote

Also we have that in the given function, as <em>x</em> increases, the fraction \dfrac{2}{x - 1} tends to 0, therefore as x increases, we have;

\lim_  {x \to \infty}  \dfrac{2}{(x - 1)} \to 0, and \  \dfrac{2}{(x - 1)}  + 4 \to 4

Therefore, as x increases, f(x) → 4, and 4 is a horizontal asymptote of the function, forming a curve that opens up and to the right in quadrant 1

When -∞ < x < 1, we also have that as <em>x</em> becomes more negative, f(x) → 4. When x = 0, \dfrac{2}{0 - 1} + 4 = 2. When <em>x</em> approaches 1 from the left, f(x) tends to -∞, forming a curve that opens down and to the left

Therefore, the correct option is on a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4.

5 0
2 years ago
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ss7ja [257]
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8 0
3 years ago
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Iteru [2.4K]

Answer:

the first one is x=3

Step-by-step explanation:

4 0
3 years ago
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Answer:

The slope of line q is -7/6

Step-by-step explanation:

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Hope this helps!

7 0
3 years ago
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