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Mama L [17]
2 years ago
8

HELP PLS IM DUM

Mathematics
1 answer:
Andrews [41]2 years ago
5 0

ur not dum

Answer:

Paul

Step-by-step explanation:

Paul earn more than monica. Though he is getting less interest but because of his higher initial amount he is getting more return.

Computing the return of both

Monica return is  100*3.4%= $3.4 in a year

Paul return is 200*%2.2=  $4.4 in a year.

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If 1.5 and 2.5 are the height and base, then just use Pythagorean theorem,
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What is an appropriate measure to record your weight?
Reil [10]
That depends on where you live.  The purpose of writing down your
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If you live in Liberia, Myanmar, or the USA, then you'd probably
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6 0
3 years ago
Given the list of numbers, 3, 2, 6, 3, 9, 5, 12, 7, if the pattern continues, what is the sum of the ninth and tenth numbers?
LekaFEV [45]

Answer:

Step-by-step explanation:

Every other one beginning with the first 3 adds 3 to the preceding number that has an odd position.

So the odd positions go up 3 6 9 12

And the next odd position is 15 which is the nineth term.

It's hard to tell what the even ones are doing. It could be anything just about. I'm guessing its a 9. So the tenth term is 9.

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If someone gives you a more consistent answer, take it.

4 0
3 years ago
What is the slope of the line passing (-3 ,4) and (2, -1)?
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5 0
3 years ago
The position of an object moving horizontally after t seconds is given by the function s equals 3 t minus t cubed​, for t greate
Anton [14]

Answer:

Step-by-step explanation:

The position of an object moving horizontally after t seconds is given by the function

s = 3t - t³

a) The object is stationary when there is no external force acting on the body. When the body is at rest, the body remains in a position and here is no distance covered by the object i.e s = 0

b) velocity is the change in displacement of a body with respect to time.

v = ds/dt

S = 3t - t³

V = ds/dt = 3-3t²

at t = 2

Velocity = 3-3(2)²

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c) acceleration is the change in velocity of a body with respect to time.

acceleration = dv/dt

If v = 3-3t²

a = dv/dt = -6t

When v = 0

0 = 3-3t²

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The acceleration of the object at v = 0 occurs at t = 1sec and -1sec

a = -6(1)

a = -6m/s²

d) Given the speed of the body v modelled by the function

v = 3-3t²

The speed is decreasing when it is less than zero as shown:

3-3t²< 0

3<3t²

1<t²

±1<t

1<t and -1<t

t>±1

t >1 and t>-1

The speed is decreasing when

3-3t²<0 and t>1 or t>-1

6 0
3 years ago
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