I hope this helps you
x=2
g (2)=2^3-3.2^2
g (2)=8-3.4
g (2)=8-12
g (2)=-4
We have this equation to start with: m/n = 5.5. To achieve the desired equation, you need to multiply the entire equation by n, giving you this equation: m = 5.5n. Hope this helps!
Answer:
Explanation Below
Step-by-step explanation:
1. -4 + | x - 1 | = 3
= -4 + | x - 1 | + 4 = 3 + 4
= | x - 1 | = 7
= x - 1 = -7 or x - 1 = 7
= x = -6 or x = 8
2. 6 + 4 | 2x + 6| = 14
= 6 + 4 | 2x + 6 | - 6 = 14 - 6
= 4 | 2x + 6 | = 8
= 4 | 2x + 6 | / 4 = 8/4
= 2x + 6 = -2 or 2x + 6 = 2
= x = -4 or x = -2
3. -10 + | -6 - x | = 1
= -10 + | -6 + x | + 10 = 1 + 10
= | -6 - x | = 11
= -6 - x = -11 or -6 - x = 11
= x = -17 or x = 5
4. | 7 - 2x | + 4 = 5
= | 7 - 2x | + 4 - 4 = 5 - 4
= | 7 - 2x | = 1
= 7 - 2x = -1 or 7 - 2x = 1
= x = 3 or x = 4
Here are the Steps:
SOLVING EQUATIONS CONTAINING ABSOLUTE VALUE(S)
Step 1: Isolate the absolute value expression.
Step2: Set the quantity inside the absolute value notation equal to + and - the quantity on the other side of the equation.
Step 3: Solve for the unknown in both equations.
Step 4: Check your answer analytically or graphically.
Hopes this Helps :D
Mark me Brainliest : )
It would be 16 more 6th graders that are not in either band or orchestra.
15 6th Graders in band
9 6th Graders in both classes
+18 6th Graders in orchestra
-----
42 6th Graders in either class
100 6th Graders in total
-42 6th Graders in either class
-------
58 6th Graders in neither class
58-42= 16 more 6th Graders that are not in either class
You're welcome :)
