All categories

3 years ago

How do i solve this?

Mathematics

1 answer:

sweet [91]3 years ago

5 0

I cant read that but if u post a better pic of it I can help u

You might be interested in

I dont think this is right

Paladinen [302]

The answer will equal 77
Cheers,Irys

5 0

3 years ago

Read 2 more answers

Joseph runs at an average rate of 15 minutes per mile. How many miles will he run after an hour?

Nikitich [7]

Answer:

4 miles

Step-by-step explanation:

15 min. / 1 mile = 60 min. / x miles

Cross multiply.

15x = 60

Divide by 15

x = 4 miles

3 0

4 years ago

Read 2 more answers

A forest fire covers 1600 acres at time t=0. the fire is growing at a rate of 9\sqrt{t} acres per hour, where t is in hours. how

babymother [125]

To solve this problem you must apply the proccedure shown below:

1. You have that the forest fire covers 1600 acres at time t=0. the fire is growing at a rate of 9√t<span> acres per hour. Therefore, you have:
</span>
1600+∫(9√t)dt (from 0 to 16)

2. Then, when you solve it, you obtain:

1600+6t^3/2=1984

3. Therefore, as you can see, the answer is: 1984 acres.

5 0

4 years ago

Solve the following system of equations. <br> y = 12 - 5x <br> 2x + 3y = 11

Sindrei [870]

Use substitution
2x + 3(12 - 5x) = 11
Distributive property
2x + 36 - 15x = 11
Combine like terms
-13x + 36 = 11
Subtract 36
-13x = -25
x = 25/13
y = 12 - 5(25/13)
y = 31/13
Solution: x = 25/13, y = 31/13

4 0

3 years ago

Suppose a family has three children of different ages. We assume that all combinations of boys and girls are equally likely. (a)

Ivan

Answer:

a) There are 8 possible combinations and each probability is 1/8.

b) The probability that it is a boy given that there are two girls is 3/8

Step-by-step explanation:

a) The sample space is given by:

BBB (3 boys)

BBG (Boy, boy, girl)

BGB (Boy, girl, boy)

BGG (Boy, girl, girl)

GBB (girl, boy, boy)

GBG (girl, boy, girl)

GGB (girl, girl, boy)

GGG (3 girls)

The probability of each combination is the same:

P(BBB)=P(B∩B∩B)= $\frac{1}{2} \frac{1}{2} \frac{1}{2}=\frac{1}{8}$

2) There are three possible combinations in which there are 2 girls and 1 boy:

BGG, GBG, GGB

So the probability is given by:

P(BGG ∪ GBG ∪ GGB)= $\frac{1}{2} \frac{1}{2} \frac{1}{2}+\frac{1}{2} \frac{1}{2} \frac{1}{2}+\frac{1}{2} \frac{1}{2} \frac{1}{2}=\frac{3}{8}$

6 0

3 years ago