In how many different ways can a badminton team with 2 members, be chosen from a group of 6 people?

Mathematics

2 answers:

jok3333 [9.3K]2 years ago

3 0

Answer:

15 ways

Step-by-step explanation:

We can choose in ⁶C₂ ways.

=> 6 x 5 / 2

=> 30/2

=> 15 ways

Nana76 [90]2 years ago

3 0

Answer:

15 ways

Step-by-step explanation:

We need 2 people from a group of 6.

Pick a random person from the 6, then group them with another person. We have 5 ways to do so.

Now, we will pick a person to group with the person who got grouped with the first person, except the first person themself. We have 4 ways to do so

Keep repeating, we will have 5 + 4 + 3 + 2 + 1 = 15 ways to choose 2 people out of 6.

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Read 2 more answers

The sum of a number and five divided by fifteen

natta225 [31]

Answer:

Option F

Step-by-step explanation:

Let the number be n.

Sum of a number and 5 is n + 5.

Sum of a number and five divided by fifteen is

( n + 5 ) / 15