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2 years ago

In how many different ways can a badminton team with 2 members, be chosen from a group of 6 people?

Mathematics

2 answers:

jok3333 [9.3K]2 years ago

3 0

Answer:

15 ways

Step-by-step explanation:

We can choose in ⁶C₂ ways.

=> 6 x 5 / 2

=> 30/2

=> 15 ways

Nana76 [90]2 years ago

3 0

Answer:

15 ways

Step-by-step explanation:

We need 2 people from a group of 6.

Pick a random person from the 6, then group them with another person. We have 5 ways to do so.

Now, we will pick a person to group with the person who got grouped with the first person, except the first person themself. We have 4 ways to do so

Keep repeating, we will have 5 + 4 + 3 + 2 + 1 = 15 ways to choose 2 people out of 6.

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For their twentieth wedding anniversary, Richard and Sylvia had a party for several of their best friends. Things were going alo

kompoz [17]

Answer:

Richard is older

Step-by-step explanation:

We can set up an inequality for both statements.

Let r equal Richard's age and s equal Sylvia's age.

"I am older than my wife."

Since Richard is speaking, the inequality would look like this:

r > s

This means Richard is older than Sylvia.

"I am younger than my husband."

Since Sylvia is speaking, the inequality would look like this:

s < r

This means that Sylvia is younger than Richard.

We can flip one inequality to "see" them from the same perspective.

Let's use s < r

To make it so that we can see the relationship from Richard's perspective, flip the entire inequality.

s < r

r > s

The inequality from the first quote is identical to this one!

Therefore, Richard is older than Sylvia.

8 0

3 years ago

Solve 2(x + 1) = 2x + 2. (1 point) ♡ 0 O All real numbers No solution 1

sattari [20]

Answer:

B. All real numbers

Step-by-step explanation:

2(x + 1) = 2x + 2

Distribute the 2 inside the parenthesis.

2x + 2 = 2x + 2

Since the two expressions are equal and will stay equal with any value, the answer to this question is All real numbers.

Example:

2(x + 1) = 2x + 2

2(5 + 1) = 2(5) + 2

2(6) = 10 + 2

12 = 12

2(x + 1) = 2x + 2

2(150 + 1) = 2(150) + 2

2(151) = 300 + 2

302 = 302

The expression is equal for any value put in x.

6 0

3 years ago

The path of a skateboarder can be modeled by the equation (x – 3)2 = –8(y – 8), where distance is in feet and air resistance is

yKpoI14uk [10]

The maximum height and horizontal distance is required.

Maximum height 8 feet; horizontal distance 16 feet

The given path is $(x-3)^2=-8(y-8)$

If the skateboarder jumps at x = 0 she will land at y = 0. However there will be at horizontal displacement.

$(x-3)^2=-8(0-8)\\\Rightarrow (x-3)^2=8^2\\\Rightarrow x-3=\pm 8\\\Rightarrow x-3=8\\\Rightarrow x=11$

$x-3=-8\\\Rightarrow x=-5$

The distance between -5 and 11 is $11-(-5)=16$

Middle point would be $\dfrac{16}{2}=8$ from $-5$ .

$-5+8=3$

So, $x=3$

The maximum height will be

$(3-3)^2=-8(y-8)\\\Rightarrow y-8=0\\\Rightarrow y=8$

The maximum height is 8 feet and the horizontal distance is 16 feet.

Learn more:

brainly.com/question/25227606

brainly.com/question/13103131

6 0

3 years ago

Read 2 more answers

Can you pls help me i need it?

Elina [12.6K]

Answer:

$114.75

Step-by-step explanation:

You have to multiply the hours by the wage. Looking at the time that the worker was in during the morning, it was a total of 4 hours. Since the wage is $13.50/hr, we would multiply 13.50 by 4.

13.50 * 4 = 54.00

So, now we have to add together the total hours in the afternoon. If we count the time, we get 4 1/2 hours. So, now we multiply 13.50 by 4.5.

13.50 * 4.5 = 60.75

Now, to find the total pay for that day, we add both the morning and the afternoon pay together.

54.00 + 60.75 = 114.75

Therefore, the pay for this day is $114.75.

6 0

2 years ago

Simplify The following equations

Kryger [21]

Mostly collect like terms
use associative property which is
(a+b)+c=a+(b+c)
and remember that:
you just use a general rule
x+x=2x
x^2+x^2=2x^2
3xy4xy=7xy
3x+4x^2=3x+4x^2
you can only add like terms( like terms are terms that are same name like x or y are differnt, and like terms have same power exg x^2 and x^3 and x^1/2 and such

so first one

3b+11c-4c-c
since they are all c except for the first one term, just assign a number for each so it simplifies to c times(11-1)+b(3-4)=c(10-1b=10c-b or

you just use a general rule
x+x=2x
x^2+x^2=2x^2
3xy4xy=7xy
3x+4x^2=3x+4x^2

second one9a-1+8c-8a+c
group like terms
(9a-8a)+(8c+c)-1=(a)+(9c)-1=a+9c-1

12c+5a+7-13c+4a
group like terms(12c-13c)+(5a+4a)+7
add like terms
-c+9a+7
the solution is 9a-c+7

-15-6c+3b-6c+9-2b
group like terms
(-15+9)+(-6c-6c)+(3b-2b)
-6+(-12c)+b=b-6-12c

the answers are:

10c-b

a+9c-1

9a-c+7

b-12c-6

5 0

3 years ago