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quester [9]
2 years ago
8

In how many different ways can a badminton team with 2 members, be chosen from a group of 6 people?

Mathematics
2 answers:
jok3333 [9.3K]2 years ago
3 0

Answer:

15 ways

Step-by-step explanation:

We can choose in ⁶C₂ ways.

=> 6 x 5 / 2

=> 30/2

=> 15 ways

Nana76 [90]2 years ago
3 0

Answer:

15 ways

Step-by-step explanation:

We need 2 people from a group of 6.

Pick a random person from the 6, then group them with another person. We have 5 ways to do so.

Now, we will pick a person to group with the person who got grouped with the first person, except the first person themself. We have 4 ways to do so

Keep repeating, we will have 5 + 4 + 3 + 2 + 1 = 15 ways to choose 2 people out of 6.

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What is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each ​
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{\bold{\red{\huge{\mathbb{QUESTION}}}}}

what is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

\bold{ \red{\star{\blue{GIVEN }}}}

TOTAL NUMBER OF ARTICLE= 7

ARTICLES FOR 30K = 3

ARTICLES FOR 12.5K = 7-3= 4

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

Average cost of 7 articles

\bold{  \green{ \star{ \orange{FORMULA \:  USED}}}}

\red{AVERAGE  =  \frac{TOTAL \:  COST}{ NUMBER  \: OF\: ARTICLES }}

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

Average \:  cost  \: of  \: 7  \: articles -  >  \\  \frac{(3 \times 30k) + (12 .5k \times 4)}{7}  \\  \frac{90k + 50k}{7}  \\  \frac{140k}{7}  \\  \blue {Average \:  cost  \: of  \: 7  \: articles -  >} \\ 20k

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The answer to this question is D) 13.9 in.

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Step-by-step explanation:

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