Answer:
-36x z^2 ( 10 y^2 z^2) ^ 1/3
Step-by-step explanation:
16. -9 ( 640 x^3 y^2 z^8) ^ 1/3
^1/3 is the cubed root
First I will separate
(ab)^y = a^y * b^y
-9 ( 640 ) ^ 1/3 x^3 ^ 1/3 y^2 ^ 1/3 z^8 ^ 1/3
Then we know a^b^c = a^(b*c)
-9 (64) ^ 1/3 (10)^ 1/3 x^(3 * 1/3) y^(2 *1/3) z^(8* 1/3)
Simplify
-9 (64) ^ 1/3 (10)^ 1/3 x^(1) y^(2 /3) z^(8/3)
-9* 4 (10)^ 1/3 x y^(2 /3) z^(8/3)
When the exponent is greater than 1, we can take out the whole number
z^ 8/3 = x^2 * x^2/3 for example
-9 *4 (10)^ 1/3 x y^(2 /3) z^2 z^(2/3)
Move everything to the left without fractional exponents
-36x z^2 ( 10 y^2 z^2) ^ 1/3
Answer:
Below in bold.
Step-by-step explanation:
Mean = (98+92+90+78+83+88+95)/7
= 89.1 to nearest tenth.
Deviations:
98 - 89.1 = 8.9
92 - 89.1 = 2.9
90 - 89.1 = 0.9
78 - 89.1 = -11.1 = 11.1 (absolute value)
83 - 89.1 = 6.1
88-89.1 = 1.1
95 - 89.1 = 5.9
So the MAD
= (8.9+2.9+0.9+11.1+6.1+1.1+5.9)/7
= 36.9/7
= 5.27
= 5.3 to nearest tenth.
Answer:
1/2
Step-by-step explanation:
Since f(x) has a domain and range of all real numbers, it's inverse also has a domain and range of all real numbers. Furthermore since every value pair of (x,y) for f(x) is unique, its inverse will also have the inverse unique value pairs (y,x).
Answer: 0.05
Step-by-step explanation:
Given : Interval for uniform distribution : [46.0 minutes, 56.0 minutes]
The probability density function will be :-
The probability that a given class period runs between 50.75 and 51.25 minutes is given by :-
Hence, the probability that a given class period runs between 50.75 and 51.25 minutes = 0.05