Find the length of AB

WILL MARK AS BRAINLIEST PLEASE HELP!!!

neonofarm [45]

Step-by-step explanation:

2x = y-10

Rewrite as: 2x + 10 = y

Therefore:

2x+10 = y

2x +7 = 2y

Subtract the equations:

2x + 10 = y

- 2x + 7 = 2y

______________

3 = -y

Therefore y = -3

Substiture y = -3 into the second equation:

2x + 7 = 2(-3)

2x + 7 = -6

2x = -13

x= -6.5

Answer : (-6.5, -3)

3 0

2 years ago

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What is 37% of 600 gkftcchkfhkfufjfvghvhchcfhcgc

Scilla [17]

Answer:

222

Step-by-step explanation:

Let me know if it is correct!

3 0

2 years ago

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✨SOLVE THE SOLUTION TO EACH SYSTEM OF INEQUALITIES ✨ PLS HELPPPPP ME

muminat

i saw its C because where the solutions are located. sorry if it’s wrong, i’m rusty

7 0

3 years ago

The plate is rotated 90° about the origin in the counterclockwise direction. In the image trapezoid, what are the coordinates of

Jet001 [13]

Answer:

The coordinates of the endpoints of the side congruent to side EF is:

E'(-8,-4) and F'(-5,-7).

Step-by-step explanation:

" when point M (h, k) is rotated about the origin O through 90° in anticlockwise direction or we can say counter clockwise. The new position of point M (h, k) will become M' (-k, h) "

We are given a trapezoid such that the vertices of trapezoid are:

E(-4,8) , F(-7,5) , G(-4,3) , H(-2,5)

Then the new coordinates after the given transformation is:

E(-4,8) → E'(-8,-4)

F(-7,5) → F'(-5,-7)

G(-4,3) → G'(-3,-4)

H(-2,5) → H'(-5,-2)

Hence the coordinates of the endpoints of the side congruent to side EF is:

E'(-8,-4) and F'(-5,-7).

4 0

3 years ago

Plz help urgent !!!! will give the brainliest !!

Mkey [24]

Answer:

$X = \begin{bmatrix}1&3\\ 2&4\end{bmatrix}$

Step-by-step explanation:

The question we have at hand is, in other words,

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix}$ - where we have to solve for the value of $X$

If we have to isolate $X$ here, then we would have to take the inverse of the following matrix ...

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}$ ... so that it should be as follows ... $\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}^{-1}$

Therefore, we can conclude that the equation as to solve for " $X$ " will be the following,

$X=\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ - First find the 2 x 2 matrix inverse of the first portion,

$\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}$ = $\frac{1}{\det \begin{pmatrix}4&2\\ 1&1\end{pmatrix}}\begin{pmatrix}1&-2\\ -1&4\end{pmatrix}$ = $\frac{1}{2}\begin{bmatrix}1&-2\\ -1&4\end{bmatrix}$ = $\begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}$

At this point we have to multiply the rows of the first matrix by the rows of the second matrix,

$X = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ ,

$X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix}$ - Simplifying this, we should get ...

$\begin{bmatrix}1&3\\ 2&4\end{bmatrix}$ ... which is our solution.

7 0

3 years ago