I. xy + 2y=3 Not linear equation because is grade 2 equation (xy).
II. x-2y = y Are linear equations in two unknowns (x and y).
III. 3x + 2y = 5 Are linear equations in two unknowns (x and y).
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Corect ansver: C) II and III only</h2><h2>
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Oh you have to make a list of things with a price make sure it adds up to that number
A = 5/6B
A = 150.60
150.60 = 5/6B
150.60 / (5/6) = B
150.60 * 6/5 = B
903.60/5 = B
180.72 = B
180.72 - 150.60 = 30.12....u save 30.12 when buying from store A
Answer: C) 163
Step-by-Step Solution:
In the Right Triangle formed to the extreme right, lets mark the angles as
∠1, ∠2 and ∠3.
Therefore, from the Figure :-
∠1 = 73°
∠2 = 90°
By Angle Sum Property :-
∠3 = 180 - (73 + 90)
∠3 = 180 - 163
=> ∠3 = 17°
The Angle which forms a Linear Pair with ∠3 is the Corresponding Angle of ∠r, and Corresponding Angles are Equal.
Therefore,
=> 180 - ∠3
= 180 - 17
=> 163°
Therefore, the Angle that forms the Linear Pair with ∠3 is 163°
This Angle is Corresponding to ∠r and hence they are Equal ie. ∠r = 163°
Hence, ∠r = 163°
Since both of the equations are equal to y...set them equal to each other.. So it will then be
x^2+3=x+5
-3 -3
x^2=x+2 ---> x^2-x-2
(x-2) (x+1)
x=2,-1
