Hey...

Mathematics

2 answers:

CaHeK987 [17]3 years ago

5 0

Answer:

$375000000$

Step-by-step explanation:

~Kandy~
Hope this helped!
Brainliest please!

arlik [135]3 years ago

5 0

Answer:

375000000

Step-by-step explanation:

I didn't cheat......

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Please answer only number 4

sdas [7]

Answer:

for question 4, 1/3 is the probability since there are 6 sides and there are two numbers on a die less than 3, 2 and 1.

2 and 1 are 2 of the 6 numbers on the die.

so 2/6

but we have to simplify!

divide 2 by 2 and 6 by 2

1/3 done!

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

If the sum of 4040 consecutive integer numbers is 2020, find out the absolute difference between the first number and the last n

bearhunter [10]

Let $x$ be the smallest of the consecutive integers summing to 2020. Then the largest integer in the sum is $x+4039,$ so our answer is $\boxed{4039}.$

For completeness, though, let's solve for the value of $x$ that satisfies the conditions of the problem. Recall that the sum of an arithmetic series with first term $a_1,$ last term $a_n,$ and $n$ terms, is $\frac{n(a_1+a_n)}{2}.$ Plugging in our known values gives us the equation $\frac{4040(2x+4039)}{2}=2020,$ which simplifies to $2x+4039=1.$ Thus, $x=-2019,$ so the 4040 consecutive integers are $-2019,-2018,\dots,-1,0,1,\dots,2018,2019,2020.$ Notice how everything except the $2020$ cancels out!