Okay, so keeping mind that the equation for area is A = L x W, look at the measurements you already have. 5.5 x 10^5 is the length, and 4.2 x 10^4 is the width. Switch them into full form and use a calculator to multiply the two for the area in meters.
550000 x 42000 = 23100000000, which in scientific form is 2.31 × 10^10. So that's answer one.
For the second, in kilometers, just take the full measurement you already have, 23100000000 m, transfer it into kilometers, 23100000 km, and then find its scientific notation, 2.31 × 10^7. That's answer two.
To answer the last question for which is more suitable, just consider what number you'd prefer to look at: a bigger number or a smaller one. Since the kilometer measurement number is smaller, its correct.
Summarily, the answers are 2.31 × 10^10, 2.31 × 10^7, and square kilometers, in that order.
ANSWER
6.63
Explanation:
Equation used: c2 = a2 + b2 ( rearranged due to having the two sides )
c2 = 12^2 + 10^2
c2 = 144 - 100
c2 = 44
c2 = 6.63 ( the square root of 44 )
Answer:
4
Step-by-step explanation:
i could be wrong
Answer:
![\[\sqrt{5}\]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B5%7D%5C%5D)
Step-by-step explanation:
The given vector is represented by (2,-1).
This can be represented in general form as (x,y) where x=2 and y=-1.
Magnitude of the vector represented as (x,y) is given by ![[\sqrt{x^{2}+y^{2}}\]](https://tex.z-dn.net/?f=%5B%5Csqrt%7Bx%5E%7B2%7D%2By%5E%7B2%7D%7D%5C%5D)
Evaluating for the given values of x and y,
![\[\sqrt{2^{2}+(-1)^{2}}\]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B2%5E%7B2%7D%2B%28-1%29%5E%7B2%7D%7D%5C%5D)
![\[=\sqrt{4+1}\]](https://tex.z-dn.net/?f=%5C%5B%3D%5Csqrt%7B4%2B1%7D%5C%5D)
![\[=\sqrt{5}\]](https://tex.z-dn.net/?f=%5C%5B%3D%5Csqrt%7B5%7D%5C%5D)
Length of the vector is
A) to find the difference you have to subtract one from the other (53-(-41)=91)
b) 15
