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2 years ago

Why is it helpful to represent fractions and division with models? (pls make answer pretty long, thanks :)

Mathematics

2 answers:

eimsori [14]2 years ago

6 0

Answer:

Whether you're teaching the meaning of fractions or fraction operations, visual models can help students connect fractions to what they already know. Division is an essential foundation for fractions. Once students can divide objects into equal groups, they can begin to grasp dividing a whole into equal parts.

Step-by-step explanation:

elena-14-01-66 [18.8K]2 years ago

4 0

Models can help students better understand what they are working with!

Please mark me has brainliest!

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VikaD [51]

Answer:

Thanks I guess

Step-by-step explanation:

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2 years ago

Read 2 more answers

Evaluate the expression 4+−4√2+−1√ and write the result in the form a+bi.

castortr0y [4]

In the expression, the real number a equals 12 and the real number b equals -16.

<h3>How to explain the information?</h3>

It should be noted that the expression given is:

= (4 - 2i)²

Therefore, we need to expand the expression. This will be:

= (4 - 2i)(4 - 2i)

= 16 -8i -8i + 4i²

= 16 -16i +4i²

Substitute -1 for i²

= 16 - 16i + 4(-1)

= 16 - 16i - 4

= 12 - 16i

Therefore, the value of the expression is 12 - 16i.

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Evaluate the expression ( 4 − 2 i )² and write the result in the form a + b i.

8 0

2 years ago

A telephone pole has a wire to its top that is anchored to the ground. The distance from the bottom of the pole to the anchor po

Bumek [7]

Answer:

The height of the pole is 105ft,

Step-by-step explanation:

Let us call $h$ the height of the pole, then we know that the distance from the bottom of the pole to the anchor point is 49, or it is $h - 49$ .

The wire length $d$ is 14 ft longer than height $h$ , hence

$d= h+14$ .

Thus we get a right triangle with hypotenuse $d= y+14$ , perpendicular $h$ , and base $h-49$ ; therefore, the Pythagorean theorem gives

$(h-49)^2+h^2 = (h+14)^2$

which upon expanding we get:

$h^2-98h+2401 = h^2+28h+196$

further simplification gives

$h^2-126h+2205=0$ ,

which is a quadratic equation with solutions

$h =21ft\\h = 105ft.$

Since the first solution $h =21ft$ will give the triangle base length of $21ft-49ft = -28ft$ which is negative; therefore, we disregard it and pick the solution $h = 105ft$ .